답안 #996513

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
996513 2024-06-10T18:09:40 Z 3lektra 악어의 지하 도시 (IOI11_crocodile) C++14
컴파일 오류
0 ms 0 KB
#include <bits/stdc++.h>
#define vi vector<int>
#define vc vector
#define pi pair<int,int>
using namespace std;

vc<vc<pi>> edg; // Edges, aka the corridors coming out from each room
vc<pi> dis; // The two minimum distances found between 2 nodes. The fastest route will just be used to calculate the second fastest, which is the oke that will be used to obtain the other distances
int fpath = -1e9-7; // Fastest path
int u, c; // Amazing the amount of situations when a node and a cost can be useful

void dijkstra(vi p){ // First Node
    priority_queue<pi> tv; // To Visit, not TeleVision or To Vandalize
    for(int i : p){
        tv.push({0,i});
        dis[i].first = 0;}
    while(!tv.empty()){
        u = tv.top().second; // The node being explored right now
        c = tv.top().first; // The cost to get to u
        tv.pop();
        
        if(dis[u].second>c){continue;} // If this path is worse then why bother
        if(u == 0){
            fpath = max(fpath, c);
            continue;}
            
        for(pi p : edg[u]){     // p.first = cost, p.second = node the path leads to
            if (p.first + c > dis[p.second].second){    // If this is path you've found is fastest than the second fastest one...
                if (p.first + c > dis[p.second].first){     // And than the fastest one...
                    dis[p.second].second = dis[p.second].first;     // Then the previously fastest one becomes the second fastest one...
                    dis[p.second].first = p.first + c;}     // This new path becomes the fastest!
                    
                else{ // But if it's not fastest than the fastest one...
                    dis[p.second].second = p.first + c;}
                    
                tv.push({dis[p.second].second, p.second});
            

            }
        }
    }
}



int travel_plan(int n, int m, vc<vi> r, vi l, int k, vi p){
    edg = vc<vc<pi>>(n);
    for(int i = 0; i < m; i++){
        edg[r[i][0]].push_back({-l[i],r[i][1]});
        edg[r[i][1]].push_back({-l[i],r[i][0]});}
    
    dis = vc<pi>(n,{-1e9-7,-1e9-7});  
        
    dijkstra(p);

    //for(pi i : dis){cout << i.first << ' ' << i.second << " -- ";}
    //cout << -fpath;
return -fpath;}

int main(){
    //cout << "Hi... this is a Jumpscare because you didn't expect to get this far >:)";
    travel_plan(5,7, {{0,2},{0,3},{3,2},{2,1},{0,1},{0,4},{3,4}},{4,3,2,10,100,7,9},2,{1,3});
  
return 0;}


Compilation message

/usr/bin/ld: /tmp/cc8YsmUt.o: in function `main':
grader.cpp:(.text.startup+0x0): multiple definition of `main'; /tmp/cczoKPWt.o:crocodile.cpp:(.text.startup+0x0): first defined here
/usr/bin/ld: /tmp/cc8YsmUt.o: in function `main':
grader.cpp:(.text.startup+0x36): undefined reference to `travel_plan(int, int, int (*) [2], int*, int, int*)'
collect2: error: ld returned 1 exit status