제출 #996284

#제출 시각아이디문제언어결과실행 시간메모리
996284dreamboyPalembang Bridges (APIO15_bridge)C++17
31 / 100
2071 ms15748 KiB
#include <bits/stdc++.h> //#include <ext/pb_ds/assoc_container.hpp> using namespace std; //using namespace __gnu_pbds; #define speed ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); #define russian setlocale(LC_ALL,"Russian_Russia.20866"); #define file freopen("onlyone.in", "r", stdin), freopen("onlyone.out", "w", stdout); #define ll long long #define ull unsigned long long #define ld long double #define pll pair<ll, ll> #define pii pair<int, int> #define all(s) s.begin(), s.end() #define pb push_back #define ins insert #define mp make_pair #define sz(x) x.size() #define F first #define S second #define lb lower_bound #define ub upper_bound #define mem(x) memset(x, 0, sizeof(x)) mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const ll N = 30010; const ll M = 600000; const ll block = 316; const ll mod = 998244353; const ll P = 263; const ld pi = acos(-1); const ll inf = 1e9; ll add(ll a, ll b) { if(a + b < 0) return a + b + mod; if(a + b >= mod) return a + b - mod; return a + b; } ll sub(ll a, ll b) { return (a - b + mod) % mod; } ll mul(ll a, ll b) { return a * 1LL * b % mod; } ll binpow(ll a, ll n) { ll res = 1LL; while(n) { if(n & 1) res = mul(res, a); // if(n % 2 == 1) a = mul(a, a); n >>= 1; //n / 2 } return res; } ll inv(ll x) {//число х в степени -1 return binpow(x, mod - 2); } void solve() { ll k, n; cin >> k >> n; ll delt = 0LL; set<ll> s; vector<pll> v; for(ll i = 1; i <= n; i++) { char a, b; ll x, y; cin >> a >> x >> b >> y; s.insert(x); s.insert(y); if(a == b) delt += abs(x - y); else v.pb({x, y}); } if(k == 1) { ll ans = 0LL; vector<ll> c; for(auto [x, y]: v) c.pb(x), c.pb(y); if(!c.empty()) { sort(all(c)); ll b = c[(int) sz(c) / 2]; for(auto [x, y]: v) { ans += (abs(b - x) + abs(b - y) + 1LL); } } cout << ans + delt << '\n'; } else { ll ans = LLONG_MAX; for(auto k1: s) { for(auto k2: s) { if(k1 == k2) continue; ll cur = 0LL; for(auto [x, y]: v) { cur += min((abs(k1 - x) + abs(k1 - y) + 1LL), (abs(k2 - x) + abs(k2 - y) + 1LL)); } ans = min(ans, cur); } } cout << ans + delt << '\n'; } } signed main() { speed; //file; int test = 1; //cin >> test; while(test--) { solve(); } }
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