제출 #99335

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
99335		Akashi	회문 (APIO14_palindrome)	C++14	73 / 100	1067 ms	53752 KiB

palindrome

#include <bits/stdc++.h>
using namespace std;

struct usu{
    int x, y, p;
    bool operator < (const usu &aux)const{
        if(x != aux.x) return x < aux.x;
        if(y != aux.y) return y < aux.y;
        return p < aux.p;
    }
};
usu L[300005];

int n, lgn;
char s[300005], T[600005];
int P[20][300005], RMQ[20][300005];
int LP[600005];
int lg[300005], SA[300005];

void build_suffix_array(){
    for(int i = 1; i <= n ; ++i) P[0][i] = s[i] - 'a' + 1;

    for(int k = 1; k <= lgn ; ++k){
        for(int i = 1; i <= n ; ++i)
            L[i] = {P[k - 1][i], ((i + (1 << (k - 1))) <= n) ? P[k - 1][i + (1 << (k - 1))] : -1, i};

        sort(L + 1, L + n + 1);
        P[k][L[1].p] = 1;
        for(int i = 2; i <= n ; ++i){
            if(L[i].x == L[i - 1].x && L[i].y == L[i - 1].y) P[k][L[i].p] = P[k][L[i - 1].p];
            else P[k][L[i].p] = i;
        }
        if(k == lgn){
            int NR = 0;
            SA[++NR] = L[1].p;
            for(int i = 2; i <= n ; ++i) SA[++NR] = L[i].p;
        }
    }
}

inline int find_lcp(int x, int y){
    int ans = 0;
    for(int k = lgn; k >= 0 ; --k){
        if(max(x + ans, y + ans) > n) continue ;
        if(P[k][x + ans] == P[k][y + ans]) ans += (1 << k);
    }
    return ans;
}

void build_lcp(){
    for(int i = 1; i < n ; ++i) RMQ[0][i] = find_lcp(SA[i], SA[i + 1]);

    for(int k = 1; k <= lgn ; ++k)
        for(int i = 1; i <= n - (1 << k) ; ++i) RMQ[k][i] = min(RMQ[k - 1][i], RMQ[k - 1][i + (1 << (k - 1))]);
}
inline int use_lcp(int x, int y){
    if(x == y) return n - x + 1;

    x = P[lgn][x], y = P[lgn][y];
    if(x > y) swap(x, y);

    int l = y - x, k = lg[l];
    return min(RMQ[k][x], RMQ[k][y - (1 << k)]);
}
inline int nrap(int x, int y){
    int st = 1, dr = P[lgn][x] - 1, Sol1 = 0, Sol2 = 0;
    while(st <= dr){
        int mij = (st + dr) / 2;
        if(use_lcp(x, SA[mij]) >= y - x + 1){
            Sol1 = max(P[lgn][x] - mij, Sol1);
            dr = mij - 1;
        }
        else st = mij + 1;
    }
    if(use_lcp(x, SA[st]) >= y - x + 1) Sol1 = max(Sol1, P[lgn][x] - st);

    st = P[lgn][x] + 1, dr = n;
    while(st <= dr){
        int mij = (st + dr) / 2;
        if(use_lcp(x, SA[mij]) >= y - x + 1){
            Sol2 = max(Sol2, mij - P[lgn][x]);
            st = mij + 1;
        }
        else dr = mij - 1;
    }
    if(use_lcp(x, SA[dr]) >= y - x + 1) Sol2 = max(Sol2, dr - P[lgn][x]);
    return Sol1 + Sol2 + 1;
}
int main()
{
//    freopen("palindrome.in", "r", stdin);
//    freopen("palindrome.out", "w", stdout);

    lg[1] = 0;
    for(int i = 2; i <= 300000 ; ++i) lg[i] = lg[i / 2] + 1;

    scanf("%s", s + 1);
    n = strlen(s + 1);
    lgn = 19;

    build_suffix_array();
    build_lcp();

    ///manacher-sama
    int NR = 0;
    T[++NR] = '.';
    for(int i = 1; i <= n ; ++i) T[++NR] = s[i], T[++NR] = '.';

    int R = 0, C = 0;
    long long Sol = 0;
    for(int i = 1; i <= NR ; ++i){
        int rad = 0;
        if(i <= R) rad = min(R - i, LP[2 * C - i]) + 1;

        while(i + rad < NR && i - rad > 0 && T[i + rad] == T[i - rad]){
            if((i + rad) % 2 == 0) Sol = max(Sol, 1LL * (rad + 1) * nrap((i - rad) / 2, (i + rad) / 2));
            ++rad;
        }
        LP[i] = rad - 1;
        if(i + rad - 1 > R){
            R = i + rad - 1;
            C = i;
        }
    }
    printf("%lld", Sol);

    return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

palindrome.cpp: In function 'int main()':
palindrome.cpp:97:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%s", s + 1);
     ~~~~~^~~~~~~~~~~~~

• Subtask 1: 8 / 8
• Subtask 2: 15 / 15
• Subtask 3: 24 / 24
• Subtask 4: 26 / 26
• Subtask 5: 0 / 27