제출 #992953

#제출 시각아이디문제언어결과실행 시간메모리
992953vyshniak_nRabbit Carrot (LMIO19_triusis)C++17
100 / 100
24 ms5480 KiB
//#pragma optimize("Ofast")
//#pragma optimize("unroll-loops")
//#pragma traget("avx,avx2")

#include <iostream>
#include <cmath>
#include <algorithm>
#include <stdio.h>
#include <cstdint>
#include <cstring>
#include <string>
#include <cstdlib>
#include <vector>
#include <bitset>
#include <map>
#include <queue>
#include <ctime>
#include <stack>
#include <set>
#include <list>
#include <random>
#include <deque>
#include <functional>
#include <iomanip>
#include <sstream>
#include <fstream>
#include <complex>
#include <numeric>
#include <cassert>
#include <array>
#include <tuple>
#include <unordered_map>
#include <unordered_set>
#include <thread>

typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;

#define el '\n'
#define ff first
#define ss second
#define pb push_back
#define pf push_front
#define popb pop_back
#define popf pop_front
#define point pair <ll, ll>
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()

using namespace std;

#include <random>
mt19937 rnd(time(0));

const ll INF = 1e18 + 10;
const ll inf = 1e9 + 10;
const ll maxn = 5e5 + 10;
const ll mod = 1e9 + 7;
const ll K = 7e6 + 100;
const ll LOG = 20;

void solve() {
    ll n, m;
    cin >> n >> m;

    vector <ll> a(n + 1);
    for (ll i = 1; i <= n; i++)
        cin >> a[i];

    vector <ll> dp(n + 1, INF);
    dp[0] = 0;

    for (ll i = 1; i <= n; i++) {
        a[i] = i * m - a[i];
        if (a[i] < 0) continue;

        ll l = 0, r = n + 1;
        while (l + 1 < r) {
            ll mid = (l + r) >> 1;
            if (dp[mid] <= a[i])
                l = mid;
            else 
                r = mid;
        }

        dp[r] = a[i];
    }

    ll ans = n;
    for (ll i = 1; i <= n; i++)
        ans -= dp[i] != INF;
    cout << ans << el;
    return;
}
signed main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0); cout.tie(0);

    int tests = 1;
    //cin >> tests;

    while (tests--) 
        solve();
    return 0;
}
/*
a[i] - a[j] <= (i - j) * m
a[i] - i * m <= a[j] - j * m
i * m - a[i] >= j * m - a[j]
*/
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