제출 #992555

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
992555		Abito	Paths (RMI21_paths)	C++17	36 / 100	679 ms	1012 KiB

Main

#include <bits/stdc++.h>
#define F first
#define S second
#define pb push_back
#define ppb pop_back
#define ep insert
#define endl '\n'
#define elif else if
#define pow pwr
#define sqrt sqrtt
//#define int long long
#define ll long long
#define y1 YONE
typedef unsigned long long ull;
using namespace std;
const int N=2005;
int n,k,tin[N],sz[N],par[N],t,v[N],tree[N],lx,rx;
vector<pair<int,ll>> adj[N];
pair<ll,int> seg[4*N+5];
ll dis[N],lazy[4*N+5],val;
bool vis[N];
void dfs(int x,int p){
    par[x]=p;
    sz[x]=1;
    t++;
    tin[x]=t;
    tree[t]=x;
    for (auto u:adj[x]){
        if (p==u.F) continue;
        v[u.F]=u.S;
        dis[u.F]=dis[x]+u.S;
        dfs(u.F,x);
        sz[x]+=sz[u.F];
    }return;
}
void build(int x,int l,int r){
    lazy[x]=0;
    if (l==r){
        seg[x]={dis[tree[l]],tree[l]};
        return;
    }int mid=(l+r)/2;
    build((x<<1),l,mid);
    build((x<<1)+1,mid+1,r);
    seg[x]=max(seg[(x<<1)],seg[(x<<1)+1]);
    return;
}
void push(int x){
    seg[(x<<1)].F+=lazy[x];
    seg[(x<<1)+1].F+=lazy[x];
    lazy[(x<<1)]+=lazy[x];
    lazy[(x<<1)+1]+=lazy[x];
    lazy[x]=0;
    return;
}
void edit(int x,int l,int r){
    if (l>rx || r<lx) return;
    if (l>=lx && r<=rx){
        seg[x].F+=val;
        lazy[x]+=val;
        return;
    }int mid=(l+r)/2;
    push(x);
    edit((x<<1),l,mid);
    edit((x<<1)+1,mid+1,r);
    seg[x]=max(seg[(x<<1)],seg[(x<<1)+1]);
    return;
}
int32_t main(){
    ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
    cin>>n>>k;
    for (int i=1;i<n;i++){
        int x,y,w;
        cin>>x>>y>>w;
        adj[x].pb({y,w});
        adj[y].pb({x,w});
    }int l=0;
    for (int i=1;i<=n;i++) l+=bool(adj[i].size()==1);
    k=min(k,l);
    for (int i=1;i<=n;i++){
        t=0;dis[i]=0;v[i]=0;par[i]=0;
        memset(vis,0,sizeof(vis));
        dfs(i,0);
        build(1,1,n);
        ll ans=0;
        for (int kk=1;kk<=k;kk++){
            int x=seg[1].S;
            //cout<<x<<' ';
            while (!vis[x] && x){
                ans+=v[x];
                lx=tin[x];
                rx=tin[x]+sz[x]-1;
                val=-v[x];
                if (v[x]) edit(1,1,n);
                v[x]=0;
                vis[x]=1;
                x=par[x];
            }
        }cout<<ans<<endl;
    }
    return 0;
}

• Subtask 1: 8 / 8
• Subtask 2: 11 / 11
• Subtask 3: 17 / 17
• Subtask 4: 0 / 20
• Subtask 5: 0 / 12
• Subtask 6: 0 / 32