Submission #991649

#	Time	Username	Problem	Language	Result	Execution time	Memory
991649		GrindMachine	Snake Escaping (JOI18_snake_escaping)	C++17	100 / 100	930 ms	34848 KiB

snake_escaping

#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2")

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
 
using namespace std;
using namespace __gnu_pbds;
 
template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
 
#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) (int)a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x,y) ((x+y-1)/(y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl
 
#define rep(i,n) for(int i = 0; i < n; ++i)
#define rep1(i,n) for(int i = 1; i <= n; ++i)
#define rev(i,s,e) for(int i = s; i >= e; --i)
#define trav(i,a) for(auto &i : a)
 
template<typename T>
void amin(T &a, T b) {
    a = min(a,b);
}
 
template<typename T>
void amax(T &a, T b) {
    a = max(a,b);
}
 
#ifdef LOCAL
#include "debug.h"
#else
#define debug(...) 42
#endif
 
/*
 
 
 
*/
 
const int MOD = 1e9 + 7;
const int N = 1e5 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;

void solve(int test_case)
{
    int n,q; cin >> n >> q;
    string s; cin >> s;
    int B = max(n/2,1);
    amin(B,7);

    vector<int> pow3(n+5);
    pow3[0] = 1;
    rep1(i,n) pow3[i] = pow3[i-1]*3;
 
    vector<pii> queries(q);
    rep(id,q){
        string t; cin >> t;
        int first_t = 0, last_t = 0;
        rep(i,sz(t)){
            ll x = 0;
            if(t[i] == '0') x = 0;
            if(t[i] == '1') x = 1;
            if(t[i] == '?') x = 2;
            if(i < B) first_t = first_t*3+x;
            else last_t = last_t*3+x;
        }
 
        queries[id] = {first_t,last_t};
    }
    
    vector<int> maskf(1<<(n-B));
    rep(i,1<<(n-B)){
        int mask = 0;
        rep(bit,n-B){
            int b = 0;
            if(i&(1<<bit)) b = 1;
            mask += pow3[bit]*b;
        }

        maskf[i] = mask;
    }

    vector<int> lsqf(pow3[n-B],inf1);
    rep(i,pow3[n-B]){
        if(i%3 == 2) lsqf[i] = 0;
        else lsqf[i] = lsqf[i/3]+1;
    }
    
    int ok[1<<B][pow3[B]];
    memset(ok,0,sizeof ok);
    ok[0][0] = (1<<29)-1;

    rep(mask1,1<<B){
        rep(mask2,pow3[B]){
            if(mask1 == 0 and mask2 == 0) conts;
            int b1 = mask1&1;
            int b2 = mask2%3;
            if(b2 == 2 or b1 == b2){
                ok[mask1][mask2] = ok[mask1>>1][mask2/3];
            }
            else{
                ok[mask1][mask2] = 0;
            }
        }
    }

    vector<int> ans(q);
    vector<int> dp(pow3[n-B]);

    rep(mask1,1<<B){
        fill(all(dp),0);
 
        rep(i,1<<n){
            int firstB = i>>(n-B);
            int lastB = i^(firstB<<(n-B));
            if(firstB != mask1) conts;
            dp[maskf[lastB]] += s[i]-'0';
        }

        rep(mask2,pow3[n-B]){
            int lsq = lsqf[mask2];
            if(lsq >= inf1) conts;
            rep(x,2){
                int mask3 = mask2-pow3[lsq]*2+pow3[lsq]*x;
                dp[mask2] += dp[mask3];
            }
        }

        rep(id,q){
            ans[id] += ok[mask1][queries[id].ff]&dp[queries[id].ss];
        }
    }
 
    rep(i,q) cout << ans[i] << endl;
}
 
int main()
{
    fastio;
 
    int t = 1;
    // cin >> t;
 
    rep1(i, t) {
        solve(i);
    }
 
    return 0;
}

• Subtask 1: 5 / 5
• Subtask 2: 7 / 7
• Subtask 3: 10 / 10
• Subtask 4: 53 / 53
• Subtask 5: 25 / 25