이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "overtaking.h"
#include <iostream>
#include <vector>
#include <algorithm>
#include <cmath>
#include <map>
using namespace std;
typedef long long ll;
vector<vector<pair<ll, ll>>> dp;
vector<vector<ll>> esim;
vector<ll> t, w, s;
ll n, x, l, m;
bool cmp(pair<ll, ll> x, pair<ll, ll> y) {
if (x.first != y.first) return x.first < y.first;
if (w[x.second] != w[y.second]) return w[x.second] < w[y.second];
return x.second < y.second;
}
void init(int L, int N, vector<ll> T, vector<int> W, int X, int M, vector<int> S) {
t.clear();
w.clear();
s.clear();
esim.clear();
dp.clear();
m = M;
l = L;
x = X;
n = 0;
for (auto& it : S) {
s.push_back(it);
}
for (ll i = 0; i < N; i++) {
if (W[i] > x) {
t.push_back(T[i]);
w.push_back(W[i]);
n++;
}
}
dp.resize(m);
esim.resize(m);
for (ll i = 0; i < n; i++) {
dp[0].push_back({ t[i], i });
}
sort(dp[0].begin(), dp[0].end(), cmp);
for (ll j = 1; j < m; j++) {
ll cur_mx = 0;
for (auto& it : dp[j - 1]) {
cur_mx = max(cur_mx, it.first + w[it.second] * 1ll * (s[j] - s[j - 1]));
dp[j].push_back({ cur_mx, it.second });
}
sort(dp[j].begin(), dp[j].end(), cmp);
map<ll, ll> mp;
for (auto& it : dp[j]) {
mp[it.second] = it.first;
}
cur_mx = 0;
for (auto& it : dp[j - 1]) {
cur_mx = max(cur_mx, mp[it.second]);
esim[j].push_back(cur_mx);
}
}
}
ll arrival_time(ll Y) {
ll cur_ind = 0;
for (auto& it : t) {
if (it < Y) cur_ind++;
}
if (cur_ind == 0) {
return l * 1ll * x;
}
ll time = Y;
for (ll i = 1; i < m; i++) {
time = max(time + (s[i] - s[i - 1]) * 1ll * x, esim[i][cur_ind - 1]);
while (cur_ind > 0 && dp[i][cur_ind - 1].first >= time) {
cur_ind--;
}
if (cur_ind == 0) {
return (l - s[i]) * 1ll * x + time;
}
}
return time;
}
/*
int main() {
int L, N, X, M, Q;
cin >> L >> N >> X >> M >> Q;
vector <ll> T(N);
vector <int> W(N), S(M);
for (auto &it : T) {
cin >> it;
}
for (auto& it : W) {
cin >> it;
}
for (auto& it : S) {
cin >> it;
}
init(L, N, T, W, X, M, S);
while (Q--) {
ll k;
cin >> k;
cout << arrival_time(k) << "\n";
}
}*/
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