제출 #98864

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
98864		SpeedOfMagic	수열 (BOI14_sequence)	C++17	42 / 100	1076 ms	12628 KiB

sequence

/** MIT License Copyright (c) 2018-2019 Vasilev Daniil **/
#include <bits/stdc++.h>
using namespace std;
template<typename T> using v = vector<T>;
#define int long long
typedef long double ld;
typedef string str;
typedef vector<int> vint;
#define rep(a, l, r) for(int a = (l); a < (r); a++)
#define pb push_back
#define fs first
#define sc second
#define sz(a) ((int) a.size())
const long long inf = 4611686018427387903; //2^62 - 1
const long double EPS = 1e-10;
#if 0  //FileIO
const string fileName = "";
ifstream fin ((fileName == "" ? "input.txt"  : fileName + ".in" ));
ofstream fout((fileName == "" ? "output.txt" : fileName + ".out"));
#define get fin >>
#define put fout <<
#else
#define get cin >>
#define put cout <<
#endif
#define eol put endl
void read() {} template<typename Arg,typename... Args> void read (Arg& arg,Args&... args){get (arg)     ;read(args...) ;}
void print(){} template<typename Arg,typename... Args> void print(Arg  arg,Args...  args){put (arg)<<" ";print(args...);}
int getInt(){int a; get a; return a;}
//code starts here
v<vint> pos;
int ans = inf;

bool has(v<char>& a, int d) { for (int i : a) if (i == d) return 1; return 0; }
int pw[9] = {1, 10, 100, 1000, 10000, 100000, 1000000, 10000000, 100000000};
void solve(v<v<char>> a, int start, int h = 0, bool lez = 1) {
    if (sz(a) == 1) {
        sort(a[0].begin(), a[0].end());
        int p = 0;
        int lz = 0;
        rep(i, 0, sz(a[0]))
            if (i == 0 || a[0][i] > a[0][i - 1]) {
                if (a[0][i] == 0)
                    lz++;
                else {
                    p = (p * 10) + a[0][i];
                    for (; lz; lz--)
                        p = (p * 10);
                }
            }

        if (lz) {
            p = 1;
            for (; lz; lz--)
                p = (p * 10);
        }

        if (p == 0 && lez)
            p = 1;
        p = p * pw[h] + start;
        ans = min(ans, p);
        return;
    } else if (sz(a) == 2) { //y = 9
        for (int i = 0; i < 9; i++) { //because 99 is useless
            v<char> r;
            for (int j : a[0])
                if (j != 9 && j != i)
                    r.pb(j);
            for (int j : a[1])
                if (j != 0 && j != i + 1)
                    r.pb(j);
            solve({r}, pw[h + 1] * i + pw[h] * 9 + start, h + 2, i == 0 && sz(a[0]));
        }
    }

    rep(y, 0, 10 - (sz(a) == 2)) {
        v<v<char>> b;
        b.pb(v<char>());
        int d = y;
        rep(i, 0, sz(a)) {
            for (int j = 0; j < 10; j++)
                if (j != d && has(a[i], j))
                    b.back().pb(j);

            d = (d + 1) % 10;
            if (d == 0 && i != sz(a) - 1)
                b.pb(v<char>());
        }

        solve(b, y * pw[h] + start, h + 1, y == 0 && sz(a[0]));
    }
}
void run() {
    int k;
    get k;
    v<v<char>> a(k);
    rep(i, 0, k) {
        int d;
        get d;
        a[i] = {(char) d};
    }

    solve(a, {});

    put ans;
}
/* 61
5
1 2 3 4 6
*//* 89
2
9 9
*//* 8
4
8 9 0 1
*//* 499
5
9 0 5 2 0
*//* 249
5
2 5 2 5 2
*//* 99
5
9 1 1 0 0
*/
signed main() {srand(time(0)); ios::sync_with_stdio(0); cin.tie(0); put fixed << setprecision(12); run(); return 0;}

• Subtask 1: 9 / 9
• Subtask 2: 33 / 33
• Subtask 3: 0 / 25
• Subtask 4: 0 / 33