Submission #987468

#	Time	Username	Problem	Language	Result	Execution time	Memory
987468		Essa2006	Fish (IOI08_fish)	C++14	95 / 100	1957 ms	65536 KiB

fish

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define endl '\n'
#define FF first
#define SS second
#define all(a) a.begin(), a.end()

const int N = 1 << 20;
int n, o, mod;

vector<int> S(2 * N, 1);

int add(int a, int b) {
    return (a + b) % mod;
}

int mul(int a, int b) {
    a %= mod, b %= mod;
    return (ll)a * b % mod;
}

void update(int id, int c) {
    id += N;
    S[id] += c;
    while (id /= 2) {
        S[id] = mul(S[id * 2], S[id * 2 + 1]);
    }
}

int get(int id, int u, int v, int l, int r) {
    if (l > v || r < u) {
        return 1;
    }

    if (l >= u && r <= v) {
        return S[id];
    }

    int md = (l + r) / 2;
    return mul(get(id * 2, u, v, l, md), get(id * 2 + 1, u, v, md + 1, r));
}

int main() {
    ios_base::sync_with_stdio(0);cin.tie(0);

    cin >> n >> o >> mod;

    vector<array<int, 2>> A(n);
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < 2; j++) {
            cin >> A[i][j];
        }
    }


    sort(all(A));

    map<int, int> mp;
    vector<bool> Done(n + 1);
    int cnt = 0;
    for (int i = n - 1; i >= 0; i--) {
        if (!Done[A[i][1]]) {
            Done[A[i][1]] = 1;
            mp[A[i][1]] = o - cnt++;
        }
        A[i][1] = mp[A[i][1]];
    }

    vector<int> Cut(n + 1, -1), Frst(n, -1);
    int j = -1;
    map<int, vector<int>> Ind;
    for (int i = 0; i < n; i++) {
        Ind[A[i][1]].push_back(i);
        while (j + 1 < i && 2 * A[j + 1][0] <= A[i][0]) {
            j++;
        }
        Cut[A[i][1]] = j;
    }

    int r = -1;
    while (r + 1 < n && ((2 * A[r + 1][0]) <= A.back()[0])) {
        r++;
        update(A[r][1], 1);
    }


    vector<int> Last(n + 1, n);
    int ans = 0;
    vector<int> Imp;
    for (int i = n - 1; i >= 0; i--) {
        int k = A[i][1];
        if (Last[k] == n) {
            Last[k] = i;
            while (r >= 0 && ((2 * A[r][0]) > A[i][0])) {
                update(A[r][1], -1);
                r--;
            }

            for (int f = S[k + N]; f > 0; f--) {
                int l = 0, r = Imp.size() - 1, last_zero = n;
                while (l <= r) {
                    int md = (l + r) / 2;
                    int cut = Cut[Imp[md]];
                    int num = upper_bound(all(Ind[k]), cut) - Ind[k].begin();
                    if (num > (f - 1)) {
                        last_zero = Imp[md], l = md + 1;
                    }
                    else {
                        r = md - 1;
                    }
                }
                int c = S[k + N];
                update(k, -(c - 1));

                ans = add(ans, get(1, 0, last_zero - 1, 0, N - 1));

                update(k, (c - 1));
                //cout << i << ' ' << f << ' ' << last_zero << endl;
            }
            Imp.push_back(k);
        }
    }

    cout << ans;
}

• Subtask 1: 4 / 4
• Subtask 2: 4 / 4
• Subtask 3: 4 / 4
• Subtask 4: 4 / 4
• Subtask 5: 4 / 4
• Subtask 6: 5 / 5
• Subtask 7: 6 / 6
• Subtask 8: 6 / 6
• Subtask 9: 6 / 6
• Subtask 10: 6 / 6
• Subtask 11: 7 / 7
• Subtask 12: 7 / 7
• Subtask 13: 7 / 7
• Subtask 14: 5 / 5
• Subtask 15: 5 / 5
• Subtask 16: 5 / 5
• Subtask 17: 5 / 5
• Subtask 18: 5 / 5
• Subtask 19: 0 / 5