Submission #986211

#	Time	Username	Problem	Language	Result	Execution time	Memory
986211		GrindMachine	Reconstruction Project (JOI22_reconstruction)	C++17	70 / 100	5047 ms	22928 KiB

reconstruction

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;

#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) (int)a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x,y) ((x+y-1)/(y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl

#define rep(i,n) for(int i = 0; i < n; ++i)
#define rep1(i,n) for(int i = 1; i <= n; ++i)
#define rev(i,s,e) for(int i = s; i >= e; --i)
#define trav(i,a) for(auto &i : a)

template<typename T>
void amin(T &a, T b) {
    a = min(a,b);
}

template<typename T>
void amax(T &a, T b) {
    a = max(a,b);
}

#ifdef LOCAL
#include "debug.h"
#else
#define debug(...) 42
#endif

/*

refs:
some solutions

*/

const int MOD = 1e9 + 7;
const int N = 500 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;

vector<pll> adj[N];

ll dfs1(ll u, ll p, ll des, ll mn){
    if(u == des){
        return mn;
    }

    ll ans = inf1;

    for(auto [v,id] : adj[u]){
        if(v == p) conts;
        amin(ans,dfs1(v,u,des,min(mn,id)));
    }

    return ans;
}

ll dfs2(ll u, ll p, ll des, ll mx){
    if(u == des){
        return mx;
    }

    ll ans = 0;

    for(auto [v,id] : adj[u]){
        if(v == p) conts;
        amax(ans,dfs2(v,u,des,max(mx,id)));
    }

    return ans;
}

void solve(int test_case)
{
    ll n,m; cin >> n >> m;
    vector<array<ll,3>> edges(m+5);

    rep1(i,m){
        ll u,v,w; cin >> u >> v >> w;
        edges[i] = {w,u,v};
    }

    sort(edges.begin()+1,edges.begin()+m+1);

    vector<ll> lx(m+5,1), rx(m+5,inf1);

    auto rem = [&](ll id){
        auto [w,u,v] = edges[id];
        adj[u].erase(find(all(adj[u]),make_pair(v,id)));
        adj[v].erase(find(all(adj[v]),make_pair(u,id)));
    };

    // find L[i]
    rep1(i,m){
        auto [w,u,v] = edges[i];
        ll j = dfs1(u,-1,v,inf1);
        if(j <= m){
            rem(j);
            lx[i] = (w+edges[j][0])/2+1;
        }
        adj[u].pb({v,i}), adj[v].pb({u,i});
    }

    // find R[i]
    rep1(i,n) adj[i].clear();

    rev(i,m,1){
        auto [w,u,v] = edges[i];
        ll j = dfs2(u,-1,v,0);
        if(j){
            rem(j);
            rx[i] = (w+edges[j][0])>>1;
        }
        adj[u].pb({v,i}), adj[v].pb({u,i});
    }

    ll q; cin >> q;

    while(q--){
        ll x; cin >> x;
        ll ans = 0;

        rep1(i,m){
            if(lx[i] <= x and x <= rx[i]){
                ans += abs(x-edges[i][0]);
            }
        }

        cout << ans << endl;
    }
}

int main()
{
    fastio;

    int t = 1;
    // cin >> t;

    rep1(i, t) {
        solve(i);
    }

    return 0;
}

• Subtask 1: 3 / 3
• Subtask 2: 4 / 4
• Subtask 3: 0 / 7
• Subtask 4: 28 / 28
• Subtask 5: 35 / 35
• Subtask 6: 0 / 23