Submission #985911

#TimeUsernameProblemLanguageResultExecution timeMemory
985911siewjhSequence (APIO23_sequence)C++17
7 / 100
833 ms129192 KiB
#include "sequence.h" #include <bits/stdc++.h> using namespace std; const int MAXN = 500005; struct node{ int s, e, m, mn, mx, lazy; node *l, *r; node (int _s, int _e){ s = _s, e = _e, m = (s + e) >> 1; mn = s, mx = e, lazy = 0; if (s != e){ l = new node(s, m); r = new node(m + 1, e); } } void update(int x, int y, int v){ if (x == s && y == e){ mn += v; mx += v; lazy += v; return; } else if (y <= m) l->update(x, y, v); else if (x > m) r->update(x, y, v); else{ l->update(x, m, v); r->update(m + 1, y, v); } mn = min(l->mn, r->mn) + lazy; mx = max(l->mx, r->mx) + lazy; } int mnq(int x, int y){ if (x == s && y == e) return mn; else if (y <= m) return l->mnq(x, y) + lazy; else if (x > m) return r->mnq(x, y) + lazy; else return min(l->mnq(x, m), r->mnq(m + 1, y)) + lazy; } int mxq(int x, int y){ if (x == s && y == e) return mx; else if (y <= m) return l->mxq(x, y) + lazy; else if (x > m) return r->mxq(x, y) + lazy; else return max(l->mxq(x, m), r->mxq(m + 1, y)) + lazy; } }; vector<int> occ[MAXN]; int sequence(int N, vector<int> A){ for (int i = 1; i <= N; i++) occ[A[i - 1]].push_back(i); node *root = new node(0, N), *root2 = new node(0, N); int ans = 0; for (int x = 1; x <= N; x++){ for (int id : occ[x]) root->update(id, N, -2); int sz = occ[x].size(); for (int l = 0, r = 0; l < sz; l++) for (; r < sz; r++){ int mxs = root2->mxq(occ[x][r], N) - root2->mnq(0, occ[x][l] - 1); int mns = root->mnq(occ[x][r], N) - root->mxq(0, occ[x][l] - 1); int len = r - l + 1; if (mns <= 0 && mxs >= 0) ans = max(ans, len); else break; } for (int id : occ[x]) root2->update(id, N, -1); } return ans; }
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