제출 #984832

#제출 시각아이디문제언어결과실행 시간메모리
984832Br3adPutovanje (COCI20_putovanje)C++17
110 / 110
101 ms35480 KiB
#include <iostream> #include <fstream> #include <iomanip> #include <algorithm> #include <functional> #include <numeric> #include <cstring> #include <string> #include <cmath> #include <vector> #include <queue> #include <stack> #include <set> #include <map> using namespace std; #define ll long long #define ull unsigned long long #define f first #define s second #define PF push_front #define PB push_back #define MP make_pair #define max(a, b) ((a > b)? a : b) #define min(a, b) ((a < b)? a : b) #define max3(a, b, c) max(max(a, b), c) #define min3(a, b, c) min(min(a, b), c) const int N = 2e5 + 5; const int M = 1e9 + 7; const int inf = 0x3f3f3f3f; const ll int INF = 1e18; struct BIT { int sz; vector<int> tree; BIT(int n) : sz(n+1), tree(n+1, 0) {}; void add(int pos, int val){ for(; pos < sz; pos += pos&-pos) tree[pos] += val; } int sum(int pos){ int ans = 0; for(; pos >= 1; pos -= pos&-pos) ans += tree[pos]; return ans; } }; vector<vector<pair<int, int>>> adj(N, vector<pair<int, int>>()); vector<vector<int>> par(20, vector<int>(N)); vector<pair<int, int>> ticket(N); vector<int> to(N), to_edge(N), tin(N), tout(N); int timer = 1; void dfs(int cur, int prev){ tin[cur] = timer++; for(auto [child, edge_id] : adj[cur]){ if(child == prev) continue; to[child] = cur; to_edge[child] = edge_id; dfs(child, cur); } tout[cur] = timer++; } bool isAncestor(int anc, int child){ return (tin[anc] <= tin[child] && tout[anc] >= tout[child]); } int get_lca(int a, int b){ if(isAncestor(a, b)) return a; int lca = b, cur = a; for(int i = 19; i >= 0; i--){ int next_cur = par[i][cur]; if(isAncestor(next_cur, b)){ lca = next_cur; }else { cur = next_cur; } } return lca; } int main(){ ios::sync_with_stdio(false); cin.tie(NULL); // ifstream cin(); // ofstream cout(); int n; cin >> n; for(int i = 1; i <= n-1; i++){ int a, b, c1, c2; cin >> a >> b >> c1 >> c2; adj[a].PB(MP(b, i)); adj[b].PB(MP(a, i)); ticket[i] = MP(c1, c2); } to[1] = 1; to_edge[1] = -1; dfs(1, -1); BIT bit(n*2); for(int i = 1; i <= n; i++) par[0][i] = to[i]; for(int i = 1; i < 20; i++){ for(int j = 1; j <= n; j++){ par[i][j] = par[i-1][par[i-1][j]]; } } for(int i = 1; i < n; i++){ int lca = get_lca(i, i+1); bit.add(tin[i], 1); bit.add(tin[i+1], 1); bit.add(tin[lca], -2); } // Check for each edge, its number of passing ll ans = 0; for(int i = 2; i <= n; i++){ int cur = bit.sum(tout[i]) - bit.sum(tin[i] - 1), ind = to_edge[i]; ans += min(1ll * ticket[ind].f * cur, ticket[ind].s); } cout << ans << endl; }
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