제출 #984478

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
984478		shjeong	밀림 점프 (APIO21_jumps)	C++17	100 / 100	1078 ms	109244 KiB

jumps

#include "jumps.h"
 
#include <iostream>
#include <cmath>
#include <algorithm>
#include <numeric>
#include <cstring>
#include <vector>
#include <string>
#include <climits>
#include <map>
#include <set>
#include <stack>
#include <queue>
#include <bitset>
#include <cassert>
#include <list>
using namespace std;
typedef long long ll;
vector<ll> v;
ll n;
ll L[202020][22];
ll R[202020][22];
ll M[202020][22];
void init(int N, std::vector<int> H) {
    n=N;
    v.resize(n+1,0);
    for(int i = 1 ; i <= n ; i++)v[i] = H[i-1];
    stack<ll> st;
    for(int i = 1 ; i <= n ; i++){
        while(st.size() and v[st.top()] < v[i]){
            M[st.top()][0] = R[st.top()][0] = i;
            st.pop();
        }
        st.push(i);
    }
    while(st.size())st.pop();
    for(int i = n ; i >= 1 ; i--){
        while(st.size() and v[st.top()] < v[i]){
            L[st.top()][0] = i;
            M[st.top()][0] = (v[i] > v[R[st.top()][0]] ? i : R[st.top()][0]);
            st.pop();
        }
        st.push(i);
    }
    for(int j = 1 ; j <= 20 ; j++){
        for(int i = 1 ; i <= n ; i++){
            L[i][j] = L[L[i][j-1]][j-1];
            R[i][j] = R[R[i][j-1]][j-1];
            M[i][j] = M[M[i][j-1]][j-1];
        }
    }
}
 
ll RMQ(ll l, ll r){
    ll ret = l;
    for(int i = 20 ; i >= 0 ; i--){
        if(R[ret][i]>0 and R[ret][i]<=r)ret = R[ret][i];
    }
    return v[ret];
}
int minimum_jumps(int A, int B, int C, int D) {
    A++; B++; C++; D++;
    ll H = RMQ(B,C-1);
    ll mx = RMQ(C,D);
    ll cur = B;
    for(int i = 20 ; i >= 0 ; i--){
        if(L[cur][i]>0 and L[cur][i]>=A and v[L[cur][i]]<=mx)cur = L[cur][i];
    }
    ll ret = 0;
    for(int i = 20 ; i >= 0 ; i--){
        if(M[cur][i]>0 and v[M[cur][i]]<=H)cur = M[cur][i], ret += (1<<i);
    }
    if(C <= R[cur][0] and R[cur][0] <= D)return ret+1;
    if(0<M[cur][0] and v[M[cur][0]]<mx){
        cur = M[cur][0], ret++;
    }
    for(int i = 20 ; i >= 0 ; i--){
        if(R[cur][i]>0 and R[cur][i]<C)cur = R[cur][i], ret += (1<<i);
    }
    if(cur<C)cur = R[cur][0], ret++;
    return C <= cur and cur <= D ? ret : -1;
}

• Subtask 1: 4 / 4
• Subtask 2: 8 / 8
• Subtask 3: 13 / 13
• Subtask 4: 12 / 12
• Subtask 5: 23 / 23
• Subtask 6: 21 / 21
• Subtask 7: 19 / 19