제출 #983372

#제출 시각아이디문제언어결과실행 시간메모리
983372hocln밀림 점프 (APIO21_jumps)C++17
0 / 100
4027 ms33984 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace __gnu_pbds; using namespace std; template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; #define all(v) v.begin(), v.end() #define logg(x) (31 - __builtin_clz(x)) #define llogg(x) (63 - __builtin_clzll(x)) #define mini(v) min_element(v.begin(), v.end()) #define maxi(v) max_element(v.begin(), v.end()) #define TIME cerr << double(clock() - st) / (double)CLOCKS_PER_SEC #define sq(a) ((a)*(a)) #ifdef hocln #include "deb.h" #else #define imie(...) "" #define debug() cerr #endif typedef long long ll; typedef pair<ll, ll> pll; typedef pair<int, int> pii; typedef long double ld; typedef tuple<ll, ll, ll> triple; typedef tuple<ll, ll, ll, ll, ll> five; typedef unsigned long long ull; const long long INF = 4e18; const int inf = 2e9; const int MN = 3e5 + 15; const int MX = 2e6 + 15; //const long long MOD = 1e9 + 7; //const long long MOD = 998244353; const long double PI = 3.141592653589793238462643383279502884197; template<typename T, typename T2> bool chmax(T& a, const T2& b) { return a < b ? a = b, 1 : 0; } template<typename T, typename T2> bool chmin(T& a, const T2& b) { return a > b ? a = b, 1 : 0; } template<typename T> using vector2 = vector<vector<T>>; const int dx[] = { 0, 0, 1, -1, 1, 1, -1, -1 }; const int dy[] = { 1, -1, 0, 0 , 1, -1, 1, -1}; std::random_device rd; std::mt19937 gen(rd()); ll random(ll low, ll high) { uniform_int_distribution<> dist(low, high); return dist(gen); } template<typename T1, typename T2> istream& operator>>(istream& is, pair<T1, T2>& p) { is >> p.first; return is >> p.second; } template<typename T> ostream& operator<<(ostream& os, const vector<T>& v) { for (auto &i: v) os << i << ' '; return os; } int tc = 0; constexpr int N = 2e5 + 15; constexpr int LOG = 20; int nxt[N][LOG], be[N][LOG]; void init(int n, vector<int>h) { stack<int>st; for(int i = 0;i < LOG;i++) nxt[n-1][i] = n - 1,be[0][i]=0; st.push(n-1); for(int i = n - 2;i >= 0;i--) { while(!st.empty() && h[st.top()] <= h[i]) st.pop(); int nx = (st.empty() ? i : st.top()); //debug()<<imie(i)imie(nx); nxt[i][0] = nx; for(int j = 1;j < LOG;j++) nxt[i][j] = nxt[nxt[i][j-1]][j-1]; st.push(i); } while(!st.empty()) st.pop(); st.push(0); for(int i = 1;i < n;i++) { while(!st.empty() && h[st.top()] <= h[i]) st.pop(); int b = (st.empty() ? i : st.top()); //debug()<<imie(i)imie(b); be[i][0] = b; for(int j = 1;j < LOG;j++) be[i][j] = be[be[i][j-1]][j-1]; st.push(i); } } int minimum_jumps(int a, int b, int c, int d) { int ans = inf; for(int j = a;j <= b;j++) { int cur = j, amt = 0; for(int k = 0;k < 20;k++) { if(nxt[cur][k] == cur) break; if(nxt[cur][k] > d) { if(k == 0) break; cur = nxt[cur][k-1]; amt += 1 << (k - 1); k = -1; } else if(nxt[cur][k] >= c && nxt[cur][k] <= d) { chmin(ans, amt + (1 << k)); break; } } } //for(int j = c;j <= d;j++) { //int cur = j, amt = 0; //for(int k = 0;k < 20;k++) { //if(be[cur][k] == cur) break; //if(be[cur][k] < a) { //if(k == 0) break; //cur = be[cur][k-1]; //amt += 1 << (k - 1); //k = -1; //} //else if(be[cur][k] >= a && be[cur][k] <= b) { //chmin(ans,amt + (1 << k)); //break; //} //} //} return (ans == inf ? -1 : ans); }
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