#define _USE_MATH_DEFINES
#include <bits/stdc++.h>
#define ff first
#define ss second
#define pb push_back
#define all(a) (a).begin(), (a).end()
#define replr(i, a, b) for (int i = int(a); i <= int(b); ++i)
#define reprl(i, a, b) for (int i = int(a); i >= int(b); --i)
#define rep(i, n) for (int i = 0; i < int(n); ++i)
#define mkp(a, b) make_pair(a, b)
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> PII;
typedef vector<int> VI;
typedef vector<PII> VPI;
typedef vector<VI> VVI;
typedef vector<VVI> VVVI;
typedef vector<VPI> VVPI;
typedef pair<ll, ll> PLL;
typedef vector<ll> VL;
typedef vector<PLL> VPL;
typedef vector<VL> VVL;
typedef vector<VVL> VVVL;
typedef vector<VPL> VVPL;
template<class T> T setmax(T& a, T b) {if (a < b) return a = b; return a;}
template<class T> T setmin(T& a, T b) {if (a < b) return a; return a = b;}
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
template<class T>
using indset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#include "sequence.h"
namespace TEST2 {
int n;
VI a;
int solve(VI A) {a = A, n = a.size();
int ans = 0;
replr(l, 0, n-1) {
indset<PII> st;
int UID = 0;
replr(r, l, n-1) {
st.insert({a[r], UID++});
int med1 = st.find_by_order((st.size()-1)/2)->ff;
int med2 = st.find_by_order(st.size()/2)->ff;
setmax(ans, int(st.order_of_key(*st.upper_bound({med1, 2e9})) - st.order_of_key(*st.lower_bound({med1, -2e9}))));
setmax(ans, int(st.order_of_key(*st.upper_bound({med2, 2e9})) - st.order_of_key(*st.lower_bound({med2, -2e9}))));
}
}
return ans;
}
};
int sequence(int n, VI a) {
return TEST2::solve(a);
return 0;
}
