Submission #979105

#TimeUsernameProblemLanguageResultExecution timeMemory
979105andrei_iorgulescuPrisoner Challenge (IOI22_prison)C++17
90 / 100
10 ms1884 KiB
#include <bits/stdc++.h> #include "prison.h" using namespace std; int n = 5000; int real_N; int trit(int x,int pos) { for (int i = 1; i <= pos; i++) x /= 3; return x % 3; } vector<vector<int>> get_real_ans(vector<vector<int>> ans) { vector<vector<int>> real_ans; real_ans.resize(ans.size()); for (int i = 0; i < ans.size(); i++) for (int j = 0; j < real_N + 1; j++) real_ans[i].push_back(ans[i][j]); return real_ans; } vector<vector<int>> devise_strategy(int N) { real_N = N; vector<vector<int>>ans; ans.resize(22); for (int i = 0; i < 22; i++) ans[i].resize(n + 1); ///A = (A - 1) / 4, B = (B - 1) / 4 ans[0][0] = 0; for (int i = 1; i <= n; i++) { int xx = (i - 1) / 4; if (xx < 625) ans[0][i] = 1; else ans[0][i] = 2; } for (int i = 1; i <= 21; i++) { for (int j = 1; j <= n; j++) { int xx = (j - 1) / 4; int nm = xx; if (i >= 3) nm %= 625; if (i >= 5) nm %= 313; if (i >= 7) nm %= 157; if (i >= 9) nm %= 79; if (i >= 12) nm %= 27; if (i >= 15) nm %= 9; if (i >= 18) nm %= 3; if (i >= 1 and i <= 2) { ans[i][0] = 1; if (nm >= 625 and i == 1) ans[i][j] = -1; else if (nm < 625 and i == 2) ans[i][j] = -2; else { if (nm % 625 < 313) ans[i][j] = 3; else ans[i][j] = 4; } } else if (i >= 3 and i <= 4) { ans[i][0] = 0; if (nm >= 313 and i == 3) ans[i][j] = -2; else if (nm < 313 and i == 4) ans[i][j] = -1; else { if (nm % 313 < 157) ans[i][j] = 5; else ans[i][j] = 6; } } else if (i >= 5 and i <= 6) { ans[i][0] = 1; if (nm >= 157 and i == 5) ans[i][j] = -1; else if (nm < 157 and i == 6) ans[i][j] = -2; else { if (nm % 157 < 79) ans[i][j] = 7; else ans[i][j] = 8; } } else if (i >= 7 and i <= 8) { ans[i][0] = 0; if (nm >= 79 and i == 7) ans[i][j] = -2; else if (nm < 79 and i == 8) ans[i][j] = -1; else { if (nm % 79 < 27) ans[i][j] = 9; else if (nm % 79 < 54) ans[i][j] = 10; else ans[i][j] = 11; } } else if (i >= 9 and i <= 11) { ans[i][0] = 1; if ((nm < 27 and i >= 10) or (nm < 54 and i == 11)) ans[i][j] = -2; else if ((nm >= 54 and i <= 10) or (nm >= 27 and i == 9)) ans[i][j] = -1; else { if (nm % 27 < 9) ans[i][j] = 12; else if (nm % 27 < 18) ans[i][j] = 13; else ans[i][j] = 14; } } else if (i >= 12 and i <= 14) { ans[i][0] = 0; if ((nm < 9 and i >= 13) or (nm < 18 and i == 14)) ans[i][j] = -1; else if ((nm >= 18 and i <= 13) or (nm >= 9 and i == 12)) ans[i][j] = -2; else { if (nm % 9 < 3) ans[i][j] = 15; else if (nm % 9 < 6) ans[i][j] = 16; else ans[i][j] = 17; } } else if (i >= 15 and i <= 17) { ans[i][0] = 1; if ((nm < 3 and i >= 16) or (nm < 6 and i == 17)) ans[i][j] = -2; else if ((nm >= 6 and i <= 16) or (nm >= 3 and i == 15)) ans[i][j] = -1; else { if (nm % 3 == 0) ans[i][j] = 18; else if (nm % 3 == 1) ans[i][j] = 19; else ans[i][j] = 20; } } else if (i >= 18 and i <= 20) { ans[i][0] = 0; if ((nm < 1 and i >= 19) or (nm < 2 and i == 20)) ans[i][j] = -1; else if ((nm >= 2 and i <= 19) or (nm >= 1 and i == 18)) ans[i][j] = -2; else { if ((j - 1) % 4 == 0) ans[i][j] = -1; else if ((j - 1) % 4 == 3) ans[i][j] = -2; else ans[i][j] = 21; } } else { ans[i][0] = 1; if ((j - 1) % 4 <= 1) ans[i][j] = -2; else ans[i][j] = -1; } } } vector<vector<int>> real_ans = get_real_ans(ans); return real_ans; } /** Idee sqrt -> Iau un B = sqrt(N), intreb primul numar si raspund cu 1 + x / B, intreb al doilea cand vad ceva sub N / B si daca da alt x / B raspund -> Daca da acelasi x / B, pun un N / B + 2 si il rog pe primul sa intrebe x % B punand N / B + 3 + x % B, la care al doilea vede si compara x % B Asta foloseste gen 2sqrt(N), 10p **/ /** Idee biti -> Vad 0, intreb de primul numar si ii pun 1 + primul bit. Al doilea vede asta si compara primii biti. La egalitate, scrie 3 si se repeta procesul -> Candva, vor da bitii diferiti Asta foloseste 3logN = 39, 26.5p **/ /** Idee biti based -> Vad 0, intreb primul numar si ii scriu 1 + primul bit. Al doilea citeste 1 / 2, compara cu primul bit din al doilea numar -> Daca e diferit de primul bit din primul numar, e gata, altfel scrie 3 / 4 reprezentand al doilea bit din al doilea numar Asta foloseste 2logN = 26, 42p **/ /** Optimizari: -> Pot folosi baza 3 si fac x = 3log3(N) = 3 * 8 = 24, 65p -> Pot sa tai putin de la ultimul bit cu o chestie actually cute: cand primul intreaba, daca e 0 sau 2 atunci clar stiu rez (fiind diferite), altfel pun +1 -> Cu ultima optimizare fac x = 3log3(N) - 3 + 1 = 22, 80p -> Optimizarea la final ar merge si in baza 4 eventual, sa fie 4log4(N) - 4 + 1, dar vine 4 * 7 - 4 + 1, prea mull -> Still, eu pot zice ca vreau in 20 de operatii sa compar (cu posibila egalitate) doua numere pana la 1250 -> 1250 -> 625 -> 313 -> 157 -> 79 -> 27 -> 9 -> 3 -> 1 cu 2 * 4 + 3 * 4 -> Deci zic asa: ma uit la A = (A - 1), B = (B - 1), A = A / 4 si B = B / 4 (am doua numere intre 0 si 1249) -> Folosesc primii 20 de biti ca sa compar prostiile astea, apoi, in caz de egalitate, eventual un bit ca sa compar A % 4 cu B % 4 (diferite) **/

Compilation message (stderr)

prison.cpp: In function 'std::vector<std::vector<int> > get_real_ans(std::vector<std::vector<int> >)':
prison.cpp:20:23: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<std::vector<int> >::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   20 |     for (int i = 0; i < ans.size(); i++)
      |                     ~~^~~~~~~~~~~~
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