Submission #978599

#TimeUsernameProblemLanguageResultExecution timeMemory
978599michifiedTorrent (COI16_torrent)C++17
0 / 100
1067 ms63348 KiB
#include <bits/stdc++.h> #define pb push_back using namespace std; struct node_t { int par; vector<int> childs; }; int n, a, b; vector<vector<int>> adj; vector<int> path; vector<node_t> nodes; class Solution { public: struct node_t { int par, reqt; vector<int> childs; }; int ru, rv; vector<node_t> nodes; void rootTree(int cur, int par) { node_t& u = nodes[cur]; if (par != -1) u.par = par; for (int v : adj[cur]) { if (v == par or (cur == ru and v == rv) or (cur == rv and v == ru)) continue; u.childs.pb(v); rootTree(v, cur); } } void dfs(int cur) { node_t& u = nodes[cur]; priority_queue<int> pq; for (int v : u.childs) { dfs(v); pq.push(nodes[v].reqt); } int t = 1; while (not pq.empty()) { u.reqt = max(u.reqt, pq.top() + t); pq.pop(); t++; } } int ans() { return max(nodes[a].reqt, nodes[b].reqt); } Solution(int ru, int rv) { // restricted vertices this -> ru = ru; this -> rv = rv; nodes.resize(n + 1); rootTree(a, -1); rootTree(b, -1); dfs(a); dfs(b); } }; void rootTree(int cur, int par) { node_t& u = nodes[cur]; if (par != -1) u.par = par; for (int v : adj[cur]) { if (v == par) continue; u.childs.pb(v); rootTree(v, cur); } } void findPath(int cur) { path.pb(cur); if (cur == a) return; findPath(nodes[cur].par); } int main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); cin >> n >> a >> b; adj.resize(n + 1); nodes.resize(n + 1); int tu, tv, i; for (i = 0; i < n - 1; i++) { cin >> tu >> tv; adj[tu].pb(tv); adj[tv].pb(tu); } rootTree(a, -1); findPath(b); int l = 0, r = path.size() - 2, mid; while (l < r - 1) { mid = (l + r) / 2; Solution left(path[mid], path[mid + 1]), right(path[mid + 1], path[mid + 2]); if (left.ans() >= right.ans()) l = mid; else r = mid; } if (path.size() == 2) { Solution sol(path[0], path[1]); cout << sol.ans(); return 0; } Solution left(path[l], path[l + 1]), right(path[l + 1], path[l + 2]); if (left.ans() > right.ans()) cout << right.ans(); else cout << left.ans(); return 0; }
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