제출 #977047

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
977047		AlperenT_	서열 (APIO23_sequence)	C++17	50 / 100	2095 ms	73040 KiB

sequence

#include "sequence.h"
#include <bits/stdc++.h>
#pragma GCC optimize("O3,unroll-loops")
#define pb push_back
#define F first
#define S second 
#define all(a) a.begin(),a.end()
#define pii pair <int,int>
#define PII pair<pii , pii>
#define ld long double
#define ll long long 
#define sz(v) (int)v.size()
#define rep(i , a , b) for(int i=a;i <= b;i++)
#define per(i , a , b) for(int i=a;i >= b;i--)
using namespace std ;
const int maxn = 5e5+10  , N = 1e5 +1  , maxq = 202   , inf = 1e9  , maxk = 2022  , mod =1e9+7 ;
int a[maxn] , n;

struct node{
  int mxp , mnp , mxs , mns , sm ;
  node(){
    mxp = mxs = -inf ;
    mnp = mns = inf ;
    sm =0 ;
  }
};
node seg[4*maxn] ;
node mrg(node a , node b){
  node r ;
  r.mxp = max(a.mxp , b.mxp + a.sm) ;
  r.mnp = min(a.mnp , b.mnp + a.sm) ;
  r.mxs = max(b.mxs , a.mxs + b.sm);
  r.mns = min(b.mns , a.mns + b.sm) ;
  r.sm = a.sm + b.sm ;
  return r ;
}
void upd(int x , int w, int p = 1, int l = 1 , int r = n){
  if(l == r){
    seg[p].mxp = seg[p].mxs = max(0 , w);
    seg[p].mnp = seg[p].mns = min(0 , w) ;
    seg[p].sm = w ;
    return ;
  }
  int pl = p<<1,pr=p<<1|1 , mid = (l+r)/2 ;
  if(mid>= x){
    upd(x,w,pl,l,mid);
  }else{
    upd(x,w,pr,mid+1,r);
  }
  seg[p] = mrg(seg[pl] , seg[pr]) ;
}
node z ; 
void query(int le ,int ri ,int p = 1, int l = 1, int r= n){
  int pl = p<<1,pr=p<<1|1 , mid = (l+r)/2 ;
  if(le > ri){
    z.mxp = z.mxs = z.mns = z.mnp = 0 ;z.sm =0 ;
    return ; 
  }
  if(le <= l && r <= ri){
    z = mrg(z , seg[p]) ;
    return;
  }
  if(mid >= ri){
    query(le,ri,pl,l,mid);
    return ;
  }
  if(mid < le){
    query(le,ri,pr,mid+1,r);
    return ;
  }
  query(le,ri,pl,l,mid) ;query(le,ri,pr,mid+1,r);
}
vector <int> vec[maxn] ;

int ch(int x){
  node nw ; 
  rep(i , 0 , 4*n){
    node x ;
    seg[i] = x;
  }
  rep(i ,1 ,n){
    upd(i , 1) ;
  }
  rep(i ,1 ,n){
    if(sz(vec[i]) < x){
      for(int j : vec[i]){
        upd(j , -1) ; 
      }
      continue ;
    }
    rep(j , 0 ,x-1){
      upd(vec[i][j] , 0) ;
    }
    rep(j , 0 ,sz(vec[i])-x){
      int l = vec[i][j] , r = vec[i][j+x-1] ;
      z=nw;query(1 , l-1);node a1 = z;
      z=nw;query(r+1 , n);node a2 = z ;
      z=nw;query(l,r);int sum = z.sm ; 
      if((sum >= 0 && sum+a1.mns+a2.mnp <= x) || (sum <= 0 && -(sum + a1.mxs + a2.mxp) <= x))return 1 ;
      upd(vec[i][j] , -1) ;
      if(i!=sz(vec[i])-x){
        upd(vec[i][j+x] , 0) ;
      }
    }
    per(j , sz(vec[i])-1 , 0){
      upd(vec[i][j] , -1) ;
    }
  }
  return 0 ;
}

int sequence(int N, vector<int> A) {
  n = N  ;
  rep(i , 1,n){
    a[i] = A[i-1] ;
    vec[a[i]].pb(i) ;
  }
  int mx = 0 ;
  rep(i , 1 , n){
    mx= max(mx ,sz(vec[i])) ;
  }
  int l = 1 , r= mx+1 ;
  while(r-l > 1){
    int mid = (l+r)/2 ;
    if(ch(mid) == 1) l = mid ;
    else r = mid ;
  }
  return l;
}

• Subtask 1: 11 / 11
• Subtask 2: 17 / 17
• Subtask 3: 0 / 7
• Subtask 4: 0 / 12
• Subtask 5: 0 / 13
• Subtask 6: 22 / 22
• Subtask 7: 0 / 18