이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
#define ll long long
using namespace std;
ll n,k,i,j,l,a[100001],sum[100001],ans,idx;
int dp[201][100001],dp2[201][100001];
vector<ll> v;
struct line{
ll k,d,idx;
};
ll val(line a,ll x){
return a.k*x+a.d;
}
double intt(line a,line b){
return double(b.d-a.d)/(a.k-b.k);
}
int main(){
ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
cin >> n >> k;
for(i=1;i<=n;i++){
cin >> a[i];
sum[i]=sum[i-1]+a[i];
}
for(l=1;l<=k;l++){
deque<line> q;
q.push_back({sum[l-1],dp[l-1][l-1]-sum[n]*sum[l-1],l-1});
for(i=l;i<n;i++){
while(q.size()>=2 && val(q.back(),sum[i])<=val(q[q.size()-2],sum[i])) q.pop_back();
dp[l][i]=sum[n]*sum[i]-sum[i]*sum[i]+val(q.back(),sum[i]);
dp2[l][i]=q.back().idx;
line cur={sum[i],dp[l-1][i]-sum[n]*sum[i],i};
while(q.size()>=2 && intt(cur,q[0])<=intt(q[0],q[1])) q.pop_front();
q.push_front(cur);
/*for(j=l-1;j<i;j++){
ll x=dp[l-1][j]+(sum[n]-sum[i])*(sum[i]-sum[j]);
if(x>=dp[l][i]){
dp[l][i]=x;
dp2[l][i]=j;
}
}*/
/*dp[l-1][j]-sum[n]*sum[j]
-sum[i]*sum[i]
sum[i]*sum[j];*/
}
}
for(i=k;i<n;i++){
if(dp[k][i]>=ans){
ans=dp[k][i];
idx=i;
}
}
for(i=k;i>=1;i--){
v.push_back(idx);
idx=dp2[i][idx];
}
reverse(v.begin(),v.end());
cout << ans << "\n";
for(i=0;i<k;i++) cout << v[i] << " ";
}
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