이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "koala.h"
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<ll> vii;
typedef pair<ll,ll> pii;
int b[100],r[100];
bool vis[100];
int minValue(int N, int W) {
// TODO: Implement Subtask 1 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
return 0;
}
int maxValue(int n, int W) {
// TODO: Implement Subtask 2 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
ll cnt=100;
for(int i=0;i<n;i++)
vis[i]=1;
while(cnt>1){
for(int i=0;i<n;i++){
if(vis[i])
b[i]=min((100/cnt),(cnt-1));
else
b[i]=0;
}
if(cnt==9){
for(int i=0;i<n;i++){
if(vis[i])
b[i]=11;
}
}
cerr<<cnt<<'\n';
playRound(b,r);
cnt=0;
for(int i=0;i<n;i++){
if(vis[i]&&r[i]<=b[i])
vis[i]=0;
if(vis[i])
cnt++;
}
}
for(int i=0;i<n;i++){
if(vis[i])
return i;
}
return 1000;
}
int greaterValue(int N, int W) {
// TODO: Implement Subtask 3 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
return 0;
}
void allValues(int N, int W, int *P) {
if (W == 2*N) {
// TODO: Implement Subtask 4 solution here.
// You may leave this block unmodified if you are not attempting this
// subtask.
} else {
// TODO: Implement Subtask 5 solution here.
// You may leave this block unmodified if you are not attempting this
// subtask.
}
}
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