oj.uz

답안 #975074

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
975074 2024-05-04T11:35:06 Z bachhoangxuan 통행료 (APIO13_toll) C++17
100 / 100
 1042 ms 20808 KB 
// Judges with GCC >= 12 only needs Ofast
// #pragma GCC optimize("O3,no-stack-protector,fast-math,unroll-loops,tree-vectorize")
// MLE optimization
// #pragma GCC optimize("conserve-stack")
// Old judges
// #pragma GCC target("sse4.2,popcnt,lzcnt,abm,mmx,fma,bmi,bmi2")
// New judges. Test with assert(__builtin_cpu_supports("avx2"));
// #pragma GCC target("avx2,popcnt,lzcnt,abm,bmi,bmi2,fma,tune=native")
// Atcoder
// #pragma GCC target("avx2,popcnt,lzcnt,abm,bmi,bmi2,fma")
/*
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> ordered_set;
- insert(x),erase(x)
- find_by_order(k): return iterator to the k-th smallest element
- order_of_key(x): the number of elements that are strictly smaller
*/
#include<bits/stdc++.h>
using namespace std;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
uniform_real_distribution<> pp(0.0,1.0);
#define int long long
#define ld long double
#define pii pair<int,int>
#define piii pair<int,pii>
#define mpp make_pair
#define fi first
#define se second
const long long inf=1e18;
const int mod=998244353;
const int maxn=300025;
const int B=650;
const int maxs=655;
const int maxm=200005;
const int maxq=1000005;
const int maxl=25;
const int maxa=1000000;
const int root=3;
int power(int a,int n){
    int res=1;
    while(n){
        if(n&1) res=res*a%mod;
        a=a*a%mod;n>>=1;
    }
    return res;
}
const int iroot=power(3,mod-2);
const int base=101;

int p[maxn],a[maxn];
int findpar(int u){return (p[u]<0?u:p[u]=findpar(p[u]));}
bool unions(int u,int v){
    u=findpar(u);v=findpar(v);
    if(u==v) return false;
    if(p[u]>p[v]) swap(p[u],p[v]);
    p[u]+=p[v];p[v]=u;
    return true;
}

void init(int n){
    for(int i=1;i<=n;i++) p[i]=-a[i];
}

int N,M,K;
int U[maxn],V[maxn],W[maxn];
vector<int> edge[25];
int par[25],val[25],cnt[25],dep[25];

void dfs(int u,int P){
    cnt[u]=-p[u];val[u]=inf;
    par[u]=P;dep[u]=dep[P]+1;
    for(int v:edge[u]) if(v!=P) dfs(v,u),cnt[u]+=cnt[v];
}

void solve(){
    cin >> N >> M >> K;
    for(int i=0;i<M;i++) cin >> U[i] >> V[i] >> W[i];
    for(int i=0;i<K;i++) cin >> U[M+i] >> V[M+i];
    for(int i=1;i<=N;i++) cin >> a[i];

    vector<int> ord(M);
    iota(ord.begin(),ord.end(),0);
    sort(ord.begin(),ord.end(),[&](int x,int y){return W[x]<W[y];});

    init(N);
    vector<int> cc,add;
    for(int i:ord) if(unions(U[i],V[i])) cc.push_back(i);
    swap(cc,ord);

    init(N);
    for(int i=0;i<K;i++) unions(U[M+i],V[M+i]);
    cc.clear();
    for(int i:ord){
        if(unions(U[i],V[i])) cc.push_back(i);
        else add.push_back(i);
    }
    init(N);
    for(int i:cc) unions(U[i],V[i]);

    vector<pii> x;
    for(int u=1;u<=N;u++) if(p[u]<0){
        x.push_back({u,-p[u]});
        //cout << u << ' ' << -p[u] << '\n';
    }
    auto get = [&](int u){
        u=findpar(u);
        for(int i=0;i<(int)x.size();i++) if(x[i].fi==u) return i+1;
        return -1LL;
    };
    int S=get(1);
    for(int i:add){
        U[i]=get(U[i]),V[i]=get(V[i]);
        //cout << i << ' ' << U[i] << ' ' << V[i] << '\n';
    }
    for(int i=0;i<K;i++){
        U[M+i]=get(U[M+i]),V[M+i]=get(V[M+i]);
        //cout << M+i << ' ' << U[M+i] << ' ' << V[M+i] << '\n';
    }
    N=(int)x.size();
    for(int i=0;i<N;i++) a[i+1]=x[i].se;

    int res=0;
    for(int mask=0;mask<(1<<K);mask++){
        init(N);
        bool check=true;
        for(int i=0;i<K;i++) if((mask>>i&1) && !unions(U[M+i],V[M+i])) check=false;
        if(!check) continue;
        cc.clear();ord.clear();
        for(int i:add){
            if(unions(U[i],V[i])) cc.push_back(i);
            else ord.push_back(i);
        }
        init(N);
        for(int i:cc) unions(U[i],V[i]);

        int rt=findpar(S);
        for(int i=1;i<=N;i++) edge[i].clear();
        for(int i=0;i<K;i++) if(mask>>i&1){
            int u=findpar(U[M+i]),v=findpar(V[M+i]);
            edge[u].push_back(v);
            edge[v].push_back(u);
        }
        dfs(rt,0);
        for(int i:ord){
            int u=findpar(U[i]),v=findpar(V[i]);
            if(dep[u]>dep[v]) swap(u,v);
            while(dep[v]>dep[u]) val[v]=min(val[v],W[i]),v=par[v];
            while(v!=u){
                val[v]=min(val[v],W[i]);
                val[u]=min(val[u],W[i]);
                u=par[u];v=par[v];
            }
        }
        int total=0;
        //cout << "mask: " << mask << '\n';
        for(int u=1;u<=N;u++) if(p[u]<0 && u!=rt){
            total+=cnt[u]*val[u];
            //cout << u << ' ' << cnt[u] << ' ' << val[u] << '\n';
        }
        //cout << total << '\n';
        res=max(res,total);
    }
    cout << res << '\n';
}

signed main(){
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);cout.tie(NULL);
    int test=1;//cin >> test;
    while(test--) solve();
}
/*
5 5 1
3 5 2
1 2 3
2 3 5
2 4 4
4 3 6
1 3
10 20 30 40 50
*/

Subtask #1
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 8540 KB Output is correct
2 Correct 1 ms 8540 KB Output is correct

Subtask #2
18.0 / 18.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 8540 KB Output is correct
2 Correct 1 ms 8540 KB Output is correct
3 Correct 3 ms 8808 KB Output is correct
4 Correct 2 ms 8540 KB Output is correct

Subtask #3
22.0 / 22.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 8540 KB Output is correct
2 Correct 1 ms 8540 KB Output is correct
3 Correct 3 ms 8808 KB Output is correct
4 Correct 2 ms 8540 KB Output is correct
5 Correct 3 ms 8796 KB Output is correct
6 Correct 3 ms 8792 KB Output is correct

Subtask #4
22.0 / 22.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 8540 KB Output is correct
2 Correct 1 ms 8540 KB Output is correct
3 Correct 3 ms 8808 KB Output is correct
4 Correct 2 ms 8540 KB Output is correct
5 Correct 3 ms 8796 KB Output is correct
6 Correct 3 ms 8792 KB Output is correct
7 Correct 137 ms 20576 KB Output is correct
8 Correct 131 ms 20688 KB Output is correct
9 Correct 133 ms 20708 KB Output is correct

Subtask #5
22.0 / 22.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 8540 KB Output is correct
2 Correct 1 ms 8540 KB Output is correct
3 Correct 3 ms 8808 KB Output is correct
4 Correct 2 ms 8540 KB Output is correct
5 Correct 3 ms 8796 KB Output is correct
6 Correct 3 ms 8792 KB Output is correct
7 Correct 137 ms 20576 KB Output is correct
8 Correct 131 ms 20688 KB Output is correct
9 Correct 133 ms 20708 KB Output is correct
10 Correct 903 ms 20576 KB Output is correct
11 Correct 1042 ms 20688 KB Output is correct
12 Correct 1016 ms 20808 KB Output is correct