Submission #97435

#	Time	Username	Problem	Language	Result	Execution time	Memory
97435		jasony123123	Calvinball championship (CEOI15_teams)	C++11	100 / 100	556 ms	604 KiB

teams

#define _CRT_SECURE_NO_WARNINGS
#include <bits/stdc++.h>
#include <array>
//#include <ext/pb_ds/tree_policy.hpp>
//#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
//using namespace __gnu_pbds;

#define FOR(i,start,end) for(int i=start;i<(int)(end);i++)
#define FORE(i,start,end) for(int i=start;i<=(int)end;i++)
#define RFOR(i,start,end) for(int i = start; i>end; i--)
#define RFORE(i,start,end) for(int i = start; i>=end; i--)
#define all(a) a.begin(), a.end()
#define mt make_tuple
#define mp make_pair
#define v vector
#define sf scanf
#define pf printf
#define dvar(x) cout << #x << " := " << x << "\n"
#define darr(x,n) FOR(i,0,n) cout << #x << "[" << i << "]" << " := " << x[i] << "\n"

typedef long long ll;
typedef long double ld;
typedef pair<int, int > pii;
typedef pair<ll, ll> pll;
//template <class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template<class T> void minn(T &a, T b) { a = min(a, b); }
template<class T> void maxx(T &a, T b) { a = max(a, b); }

void io() {
#ifdef LOCAL_PROJECT 
	freopen("input.in", "r", stdin); freopen("output.out", "w", stdout);
#else
#endif
	ios_base::sync_with_stdio(false); cin.tie(NULL);
}

const ll INF = 1e14;
/***********************CEOI 2015 D1 Calvin*****************************************/
const int MOD = 1000007;
inline int add(int a, int b) { return (a + b) % MOD; }
inline int mul(int a, int b) { return (1LL * a*b) % MOD; }

int n, nums[10099], seen[10099];
array<int, 10099> dpold, dpcur;

int main() {
	io();
	cin >> n;
	FOR(i, 0, n) cin >> nums[i];
	seen[0] = nums[0];
	FOR(i, 1, n) seen[i] = max(nums[i], seen[i - 1]);
	int ans = 1;
	RFORE(i, n - 1, 0) {
		if (n - 1 - i == 0)
			fill(all(dpcur), 1);
		else {
			swap(dpold, dpcur);
			FOR(s, 1, n)
				dpcur[s] = add(mul(s, dpold[s]), dpold[s + 1]);
		}

		ans = add(ans, mul(nums[i] - 1, dpcur[seen[i - 1]]));
	}
	cout << ans << "\n";
}

• Subtask 1: 10 / 10
• Subtask 2: 10 / 10
• Subtask 3: 10 / 10
• Subtask 4: 10 / 10
• Subtask 5: 10 / 10
• Subtask 6: 10 / 10
• Subtask 7: 10 / 10
• Subtask 8: 10 / 10
• Subtask 9: 10 / 10
• Subtask 10: 10 / 10