이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
typedef long long ll;
template <typename T> class Vector : public std::vector<T> {
public:
using std::vector<T>::vector;
std::vector<ll> psum;
void calculate_prefix_sum() {
psum.resize(this->size());
std::partial_sum(this->begin(), this->end(), psum.begin());
}
T sum(ll a, ll b) {
if (a > b) {
return 0;
}
T ans = psum[b];
if (a - 1 >= 0) {
ans -= psum[a - 1];
}
return ans;
}
};
const ll N = 1e5 + 1, K = 201;
const ll inf = 1e15;
class Ans {
public:
ll tot;
ll cur;
ll idx;
};
bool operator<(const Ans &a, const Ans &b) {
return a.tot < b.tot;
}
Ans dp[N][K];
int main() {
ll n, k;
std::cin >> n >> k;
Vector<ll> a(n);
for (auto &i : a) {
std::cin >> i;
}
a.calculate_prefix_sum();
for (ll i = n - 1; i >= 0; -- i) {
for (ll j = 0; j <= k; ++ j) {
if (i == n - 1) {
if (j != 0) {
dp[i][j].tot = -inf;
} else {
dp[i][j].tot = 0;
}
continue;
}
if (j == 0) {
dp[i][j].tot = 0;
continue;
}
dp[i][j].tot = 0;
for (ll c = i; c < n - 1; c++) {
ll cur = a.sum(i, c) * a.sum(c + 1, n - 1);
dp[i][j] = std::max(dp[i][j], {cur + dp[c + 1][j - 1].tot, cur, c + 1});
}
}
}
std::cout << dp[0][k].tot << "\n";
ll cur = 0;
ll ops = k;
while (ops > 0) {
std::cout << dp[cur][ops].idx << " ";
cur = dp[cur][ops].idx;
ops--;
}
}
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