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답안 #973023

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
973023 2024-05-01T12:33:34 Z sleepntsheep Palembang Bridges (APIO15_bridge) C
22 / 100
 43 ms 5212 KB 
#include <stdio.h>
#include <stdlib.h>
#define MAX_N 100000

int min(int a,int b){return a<b?a:b;}
int max(int a,int b){return a>b?a:b;}
int cmpr(const void*a,const void*b){return *(const int*)a - *(const int*)b;}

int n, k, c[1+(MAX_N<<1)], p, s[MAX_N], t[MAX_N], e[MAX_N], o, temp;long long pref[MAX_N];
int cmpr2(const void*a,const void*b){int i=*(const int*)a,j=*(const int*)b;long long dir=(s[i]+t[i]+0ll)-(s[j]+t[j]);return dir<0?-1:dir>0?1:0;}
long long cost, z = 1e18;

#define MM 400000
int ha[MM],hl[MM],hr[MM],halc=0;char hs[MM];
int lt(int a,int b){return a<b;}
int gt(int a,int b){return a>b;}
int hmerge(int l,int r,int(*lt)(int,int))
{
    if(!l||!r)return l^r;
    if(lt(ha[l],ha[r]))return hmerge(r,l,lt);
    hr[l]=hmerge(hr[l],r,lt);
    if(hs[hr[l]]>=hs[hl[l]])temp=hr[l],hr[l]=hl[l],hl[l]=temp;
    hs[l]=hs[hr[l]]+1;
    return l;
}
int hpop(int v,int(*lt)(int,int)) { return hmerge(hl[v],hr[v], lt); }
int hnode(int k){int p=++halc;hs[p]=1;hl[p]=hr[p]=0;ha[p]=k;return p;}
int hinsert(int v,int k,int(*lt)(int,int)){return hmerge(v,hnode(k),lt);}

/* sliding median */
int lo, hi, losz, hisz;
long long losum,hisum;

void ins(int x)
{
    if(losz>0&&ha[lo]>x)
    {
        hi=hinsert(hi,x,gt);
        ++hisz,hisum+=x;
        while(losz<hisz)
            hisum-=ha[hi],losum+=ha[hi],lo=hinsert(lo,ha[hi],lt),hi=hpop(hi,gt),--hisz,++losz;
    }
    else
    {
        lo=hinsert(lo,x,lt);
        ++losz,losum+=x;
        while(hisz+1<losz)
            losum-=ha[lo],hisum+=ha[lo],hi=hinsert(hi,ha[lo],gt),lo=hpop(lo,lt),--losz,++hisz;
    }
}

int main()
{
    scanf("%d%d", &k, &n);
    for (int ss, tt, i = 0; i < n; ++i)
    {
        char bb, cc;
        scanf(" %c%d %c%d",&bb,&ss,&cc,&tt);
        if(bb==cc) cost += abs(tt-ss);
        else s[o]=min(ss,tt),t[o]=max(ss,tt),e[o++]=o,c[++p] = ss, c[++p] = tt,++cost;
    }

    if(o<2)k=1;

    if(k==1)
    {
        qsort(c+1, p, sizeof*c, cmpr);
        for(int j=1;j<=p;++j) cost += abs(c[p/2] - c[j]);
        printf("%lld\n", cost);
        return 0;
    }

    qsort(e,o,sizeof*e,cmpr2);

    for(int i=0;i<o;++i)
        ins(s[e[i]]),ins(t[e[i]]), pref[i] = ha[lo]*1ll*losz-losum+hisum-hisz*1ll*ha[lo];

    hi=lo=halc=hisz=losz=hisum=losum=0;
    for(int i=o-1;i>=1;--i)
    {
        ins(s[e[i]]),ins(t[e[i]]);
        long long suf=ha[lo]*1ll*losz-losum+hisum-hisz*1ll*ha[lo];
        if(suf+pref[i-1]<z)z=suf+pref[i-1];
    }
    if(pref[o-1]<z)z=pref[o-1];

    printf("%lld",z+cost);
}

Compilation message

bridge.c: In function 'main':
bridge.c:60:49: warning: operation on 'o' may be undefined [-Wsequence-point]
   60 |         else s[o]=min(ss,tt),t[o]=max(ss,tt),e[o++]=o,c[++p] = ss, c[++p] = tt,++cost;
      |                                                ~^~
bridge.c:54:5: warning: ignoring return value of 'scanf' declared with attribute 'warn_unused_result' [-Wunused-result]
   54 |     scanf("%d%d", &k, &n);
      |     ^~~~~~~~~~~~~~~~~~~~~
bridge.c:58:9: warning: ignoring return value of 'scanf' declared with attribute 'warn_unused_result' [-Wunused-result]
   58 |         scanf(" %c%d %c%d",&bb,&ss,&cc,&tt);
      |         ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
8.0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 2396 KB Output is correct
2 Correct 0 ms 2396 KB Output is correct
3 Correct 1 ms 2396 KB Output is correct
4 Correct 1 ms 2396 KB Output is correct
5 Correct 1 ms 2396 KB Output is correct
6 Correct 1 ms 2396 KB Output is correct
7 Correct 1 ms 2396 KB Output is correct
8 Correct 1 ms 2396 KB Output is correct
9 Correct 1 ms 2396 KB Output is correct
10 Correct 1 ms 2396 KB Output is correct
11 Correct 1 ms 2396 KB Output is correct

Subtask #2
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 2396 KB Output is correct
2 Correct 0 ms 2396 KB Output is correct
3 Correct 1 ms 2396 KB Output is correct
4 Correct 1 ms 2396 KB Output is correct
5 Correct 1 ms 2396 KB Output is correct
6 Correct 1 ms 2396 KB Output is correct
7 Correct 1 ms 2396 KB Output is correct
8 Correct 1 ms 2396 KB Output is correct
9 Correct 1 ms 2396 KB Output is correct
10 Correct 1 ms 2396 KB Output is correct
11 Correct 1 ms 2396 KB Output is correct
12 Correct 25 ms 4972 KB Output is correct
13 Correct 43 ms 5212 KB Output is correct
14 Correct 34 ms 4856 KB Output is correct
15 Correct 25 ms 3892 KB Output is correct
16 Correct 28 ms 4956 KB Output is correct
17 Correct 28 ms 4692 KB Output is correct
18 Correct 28 ms 5212 KB Output is correct
19 Correct 37 ms 5200 KB Output is correct
20 Correct 30 ms 4948 KB Output is correct
21 Correct 30 ms 5200 KB Output is correct

Subtask #3
0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 2392 KB Output is correct
2 Correct 1 ms 2396 KB Output is correct
3 Correct 1 ms 4444 KB Output is correct
4 Incorrect 1 ms 4444 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #4
0 / 32.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 2396 KB Output is correct
2 Correct 0 ms 2396 KB Output is correct
3 Correct 1 ms 4440 KB Output is correct
4 Incorrect 1 ms 4444 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #5
0 / 37.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 2396 KB Output is correct
2 Correct 0 ms 2396 KB Output is correct
3 Correct 1 ms 4444 KB Output is correct
4 Incorrect 1 ms 4444 KB Output isn't correct
5 Halted 0 ms 0 KB -