제출 #972640

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
972640		TheSahib	사이버랜드 (APIO23_cyberland)	C++17	97 / 100	3052 ms	195152 KiB

cyberland

#include "cyberland.h"
#include <bits/stdc++.h>
 
#define ll long long
#define pii pair<int, int>
using namespace std;
 
const ll oo = 1e18;
const int MAX = 1e5 + 5;
const int MAXK = 70;
 
struct edge{
    int u, c;
};
 
int n, k, f;
int A[MAX];
vector<edge> g[MAX];
bool visited[MAX];
 
vector<int> starts;
void dfs(int node){
    visited[node] = 1;
    for(auto& e:g[node]){
        if(visited[e.u]) continue;
        dfs(e.u);
    }
}
 
double dist[MAXK + 1][MAX];
void dijkstra(){
    priority_queue<pair<double, pii>> st;
    for (int j = 0; j <= k; j++)
    {
        for (int i = 0; i < n; i++)
        {
            dist[j][i] = oo;
        }
    }
    
    for(int a:starts){
        dist[k][a] = 0;
        st.push({0, {a, k}});
    }
    while(!st.empty()){
        double d = -st.top().first;
        int node = st.top().second.first;
        int l = st.top().second.second;
        st.pop();
        if(dist[l][node] < d) continue;
 
        for(auto& e:g[node]){
            double b = d + e.c;
            
            if(b < dist[l][e.u]){
                dist[l][e.u] = b;
                st.push({-dist[l][e.u], {e.u, l}});
            }
            if(l == 0 || A[e.u] != 2) continue;
            if(b / 2 < dist[l - 1][e.u]){
                dist[l - 1][e.u] = b / 2;
                st.push({-dist[l - 1][e.u], {e.u, l - 1}});
            }
        }
    }
}
 
 
double solve(int N, int M, int K, int H, vector<int> x, vector<int> y, vector<int> c, vector<int> arr) {
    n = N;
    k = min(MAXK, K);
    f = H;
    starts.clear();
    for (int i = 0; i < n; i++)
    {
        A[i] = arr[i];
        g[i].clear();
        visited[i] = 0;
    }
    
    for (int i = 0; i < M; i++)
    {
        g[x[i]].push_back({y[i], c[i]});
        g[y[i]].push_back({x[i], c[i]});
    }
    g[f].clear();
    dfs(0);
    starts.push_back(0);
    for (int i = 0; i < n; i++)
    {
        if(visited[i] && A[i] == 0){
            starts.push_back(i);
        }
    }
    dijkstra();
    double ans = oo;
    for(int i = 0; i <= k; ++i){
        ans = min(ans, dist[i][f]);
    }
    if(ans == oo){
        return -1;
    }
    else{
        return ans;
    }
}

• Subtask 1: 5 / 5
• Subtask 2: 8 / 8
• Subtask 3: 13 / 13
• Subtask 4: 19 / 19
• Subtask 5: 7 / 7
• Subtask 6: 16 / 16
• Subtask 7: 29 / 29
• Subtask 8: 0 / 3