이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define pll pair<ll,ll>
#define pii pair<int,int>
#define fs first
#define sc second
#define tlll tuple<ll,ll,ll>
const int mxn = 2e5+10;
vector<pii> tree[mxn];
int dp[mxn][2];
int N;
int ans = 0;
vector<pii> v[mxn];
void dfs(int now,int par){
dp[now][0] = 0;
dp[now][1] = -1e9;
for(auto [nxt,w]:tree[now]){
if(nxt == par)continue;
dfs(nxt,now);
dp[now][0] += max(dp[nxt][0],dp[nxt][1]+w);
v[now].push_back(pii(dp[nxt][0]+w-max(dp[nxt][0],dp[nxt][1]+w),nxt));
}
sort(v[now].rbegin(),v[now].rend());
if(!v[now].empty())dp[now][1] = dp[now][0]+v[now][0].fs;
return;
}
void dfs2(int now,int par){
ans = max(ans,dp[now][0]);
sort(v[now].rbegin(),v[now].rend());
for(auto [nxt,w]:tree[now]){
if(nxt == par)continue;
int dp0 = dp[now][0]-max(dp[nxt][0],dp[nxt][1]+w);
int dp1 = -1e9;
if(v[now][0].sc != nxt)dp1 = dp0+v[now][0].fs;
else if(v[now].size()>1)dp1 = dp0+v[now][1].fs;
dp[nxt][0] += max(dp0,dp1+w);
v[nxt].push_back(pii(dp0+w-max(dp0,dp1+w),now));
dfs2(nxt,now);
}
return;
}
int main(){
ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
cin>>N;
for(int i = 1;i<N;i++){
int a,b,c;
cin>>a>>b>>c;
tree[a].push_back(pii(b,c));
tree[b].push_back(pii(a,c));
}
dfs(1,1);
dfs2(1,1);
cout<<ans<<'\n';
return 0;
}
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