제출 #972022

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
972022		0x34c	Cloud Computing (CEOI18_clo)	C++17	0 / 100	198 ms	5584 KiB

clo

#include <bits/stdc++.h>
#define ll long long
#define pii pair<int, int>
#define endl '\n'
#define int ll

using namespace std;

struct node
{
    int c, f, v;
};

const int MAX_C = 201;
const int INF = 1e9;

signed main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0);

    int N, M;
    cin >> N;

    vector<node> pc(N);
    for (int i = 0; i < N; i++)
    {
        int c, f, v;
        cin >> c >> f >> v;

        pc[i] = {c, f, v};
    }

    cin >> M;
    vector<node> qr(M);
    for (int i = 0; i < M; i++)
    {
        int c, f, v;
        cin >> c >> f >> v;

        qr[i] = {c, f, v};
    }

    sort(pc.begin(), pc.end(), [&](node &a, node &b)
         {  if(a.f == b.f) return a.c > b.c; return a.f > b.f; });
    sort(qr.begin(), qr.end(), [&](node &a, node &b)
         { if(a.f == b.f) return a.c > b.c; return a.f > b.f; });

    int dp[2][N + 1][MAX_C];
    for (int i = 0; i < 2; i++)
        for (int j = 0; j <= N; j++)
            for (int c = 0; c < MAX_C; c++)
                dp[i][j][c] = -INF;

    int cur = 0, nxt = 1;
    dp[0][0][0] = 0;
    int mx = 0;
    for (int i = 0; i <= M; i++)
    {
        for (int j = 0; j <= N; j++)
        {
            for (int c = MAX_C - 1; c >= 0; c--)
            {
                if (dp[cur][j][c] == -INF)
                    continue;

                // skip zakazku
                if (i + 1 <= M)
                {
                    dp[nxt][j][c] = max(dp[nxt][j][c], dp[cur][j][c]);
                    mx = max(mx, dp[nxt][j][c]);
                }

                if (j + 1 <= N)
                {
                    // skip pc
                    dp[cur][j + 1][c] = max(dp[cur][j + 1][c], dp[cur][j][c]);
                    mx = max(mx, dp[cur][j + 1][c]);
                }

                // take cores
                if (j + 1 <= M && i < N && qr[i].f <= pc[j].f && c + pc[j].c < MAX_C)
                {
                    dp[cur][j + 1][c + pc[j].c] = max(dp[cur][j + 1][c + pc[j].c], dp[cur][j][c] - pc[j].v);
                    mx = max(mx, dp[cur][j + 1][c + pc[j].c]);
                }

                // // take next
                // if (qr[i].f <= pc[j].f && qr[i].c <= c + pc[j].c)
                // {
                //     dp[nxt][j + 1][c + pc[j].c - qr[i].c] = max(dp[nxt][j + 1][c + pc[j].c - qr[i].c], dp[cur][j][c] + (qr[i].v - pc[j].v));
                //     mx = max(mx, dp[nxt][j + 1][c + pc[j].c - qr[i].c]);
                // }

                // take using c
                if (i < N && qr[i].c <= c)
                {
                    dp[nxt][j][c - qr[i].c] = max(dp[nxt][j][c - qr[i].c], dp[cur][j][c] + qr[i].v);
                    mx = max(mx, dp[nxt][j][c - qr[i].c]);
                }
            }
        }
        swap(cur, nxt);
        for (int j = 0; j <= N; j++)
            for (int c = 0; c < MAX_C; c++)
                dp[nxt][j][c] = -INF;
    }
    cout << mx << endl;
}

• Subtask 1: 0 / 18
• Subtask 2: 0 / 18
• Subtask 3: 0 / 18
• Subtask 4: 0 / 18
• Subtask 5: 0 / 18
• Subtask 6: 0 / 10