이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long int ll;
typedef pair<int,int> ii;
const int N = 5e5 + 5;
const int LOG = 20;
int n,a[N],rmq[N][LOG];
short int logtwo[N];
void build() {
logtwo[0] = -1;
for (int i = 1 ; i <= n ; i++) {
rmq[i][0] = a[i];
logtwo[i] = logtwo[i / 2] + 1;
}
for (int i = 1 ; i < LOG ; i++)
for (int j = 1 ; j <= n ; j++)
rmq[j][i] = max(rmq[j][i - 1],rmq[min(n,j + (1 << (i - 1)))][i - 1]);
}
int query (int l,int r) {
l = max(l,1);
r = min(r,n);
if (l > r)
return -1e8;
int j = logtwo[r - l + 1];
return max(rmq[l][j],rmq[r - (1 << j) + 1][j]);
}
int solve_left(int x) {
int mx = sqrt(x - 1) + 1,lst = x,res = 0;
for (int i = 1 ; i <= mx ; i++) {
int l = x - i * i;
res = max(res,query(l,lst - 1) - a[x] + i);
lst = l;
}
return res;
}
int solve_right(int x) {
int mx = sqrt(n - x) + 1,lst = x,res = 0;
for (int i = 1 ; i <= mx ; i++) {
int r = x + i * i;
res = max(res,query(lst + 1,r) - a[x] + i);
lst = r;
}
return res;
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL); cout.tie(NULL);
cin >> n;
for (int i = 1 ; i <= n ; i++)
cin >> a[i];
build();
for (int i = 1 ; i <= n ; i++)
cout << max(solve_left(i),solve_right(i)) << "\n";
}
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