제출 #969321

#제출 시각아이디문제언어결과실행 시간메모리
969321xjonwangOsmosmjerka (COCI17_osmosmjerka)C++17
120 / 160
4019 ms33368 KiB
#include <bits/stdc++.h> using namespace std; #define ll long long #define ld long double #define ar array #define str string #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace __gnu_pbds; template <typename T> using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; #define vt vector #define pb push_back #define all(c) (c).begin(), (c).end() #define sz(x) (int)(x).size() #define pll pair<ll, ll> #define pii pair<int, int> #define f first #define s second #define F_OR(i, a, b, s) for (int i=(a); (s)>0?i<(b):i>(b); i+=(s)) #define F_OR1(e) F_OR(i, 0, e, 1) #define F_OR2(i, e) F_OR(i, 0, e, 1) #define F_OR3(i, b, e) F_OR(i, b, e, 1) #define F_OR4(i, b, e, s) F_OR(i, b, e, s) #define GET5(a, b, c, d, e, ...) e #define F_ORC(...) GET5(__VA_ARGS__, F_OR4, F_OR3, F_OR2, F_OR1) #define FOR(...) F_ORC(__VA_ARGS__)(__VA_ARGS__) #define EACH(x, a) for (auto& x: a) #define MOD ((int)1e9+7) template<class T> bool umin(T& a, const T& b) { return b<a?a=b, 1:0; } template<class T> bool umax(T& a, const T& b) { return a<b?a=b, 1:0; } ll FIRSTTRUE(function<bool(ll)> f, ll lb, ll rb) { while(lb<rb) { ll mb=(lb+rb)/2; f(mb)?rb=mb:lb=mb+1; } return lb; } ll LASTTRUE(function<bool(ll)> f, ll lb, ll rb) { while(lb<rb) { ll mb=(lb+rb+1)/2; f(mb)?lb=mb:rb=mb-1; } return lb; } template<class A> void read(vt<A>& v); template<class A, size_t S> void read(ar<A, S>& a); template<class A, class B> void read(pair<A, B>& x); template<class T> void read(T& x) { cin >> x; } void read(double& d) { string t; read(t); d=stod(t); } void read(long double& d) { string t; read(t); d=stold(t); } template<class H, class... T> void read(H& h, T&... t) { read(h); read(t...); } template<class A> void read(vt<A>& x) { EACH(a, x) read(a); } template<class A, size_t S> void read(array<A, S>& x) { EACH(a, x) read(a); } template<class A, class B> void read(pair<A, B>& x) { cin >> x.first >> x.second; } string to_string(char c) { return string(1, c); } string to_string(bool b) { return b?"true":"false"; } string to_string(const char* s) { return string(s); } string to_string(string s) { return s; } string to_string(vt<bool> v) { string res; FOR(sz(v)) res+=char('0'+v[i]); return res; } template<size_t S> string to_string(bitset<S> b) { string res; FOR(S) res+=char('0'+b[i]); return res; } template<class T> string to_string(T v) { bool f=1; string res; EACH(x, v) { if(!f) res+=' '; f=0; res+=to_string(x); } return res; } template<class A, class B> string to_string(pair<A, B>& x) { return to_string(x.first) + ' ' + to_string(x.second); } template<class A> void write(A x) { cout << to_string(x); } template<class H, class... T> void write(const H& h, const T&... t) { write(h); write(t...); } void print() { write("\n"); } template<class H, class... T> void print(const H& h, const T&... t) { write(h); if(sizeof...(t)) write(' '); print(t...); } mt19937 rng((uint32_t)chrono::steady_clock::now().time_since_epoch().count()); using H = ar<int,4>; // bases not too close to ends H makeH(char c) { return {c,c}; } uniform_int_distribution<int> BDIST(0.1*MOD,0.9*MOD); const H base{BDIST(rng),BDIST(rng), BDIST(rng), BDIST(rng)}; H operator+(H l, H r) { FOR(4) if ((l[i] += r[i]) >= MOD) l[i] -= MOD; return l; } H operator-(H l, H r) { FOR(4) if ((l[i] -= r[i]) < 0) l[i] += MOD; return l; } H operator*(H l, H r) { FOR(4) l[i] = (ll)l[i]*r[i]%MOD; return l; } vt<H> pows{{1,1}}; struct HashRange { str S; vt<H> cum{{}}; void add(char c) { S += c; cum.pb(base*cum.back()+makeH(c)); } void add(str s) { EACH(c,s) add(c); } void extend(int len) { while (sz(pows) <= len) pows.pb(base*pows.back()); } H hash(int l, int r) { int len = r+1-l; extend(len); return cum[r+1]-pows[len]*cum[l]; } }; int dc[4]={1, 1, -1, -1}, dr[4]={1, -1, 1, -1}; int main() { ios::sync_with_stdio(0); cin.tie(0); ll n, m, k; read(n, m, k); ll mi=min(n, m); vt<string> v(n); read(v); map<H, ll> cnt; umin(k, n*m/gcd(n, m)); FOR(n) { HashRange hr1; FOR(j, k+m) hr1.add(v[i][j%m]); FOR(j, m) cnt[hr1.hash(j, j+k-1)]++; HashRange hr2; FOR(j, k+m) hr2.add(v[i][m-1-j%m]); FOR(j, m) cnt[hr2.hash(j, j+k-1)]++; } FOR(m) { HashRange hr1; FOR(j, k+n) hr1.add(v[j%n][i]); FOR(j, n) cnt[hr1.hash(j, j+k-1)]++; HashRange hr2; FOR(j, k+n) hr2.add(v[n-1-j%n][i]); FOR(j, n) cnt[hr2.hash(j, j+k-1)]++; FOR(h, 4) { HashRange hr; FOR(j, k+mi) hr.add(v[((j*dr[h])%n+n)%n][((i+j*dc[h])%m+m)%m]); FOR(j, mi) cnt[hr.hash(j, j+k-1)]++; } } ll num=0, denom=m*m*n*n*64; for (auto [k, v] : cnt) num+=v*v; cout << num/gcd(num, denom) << "/" << denom/gcd(num, denom) << endl; }
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