이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
 
#define           f     first
#define           s     second
#define           pb    push_back
#define           ep    emplace
#define           eb    emplace_back
#define           lb    lower_bound
#define           ub    upper_bound
#define       all(x)    x.begin(), x.end()
#define      rall(x)    x.rbegin(), x.rend()
#define   uniquev(v)    sort(all(v)), (v).resize(unique(all(v)) - (v).begin())
#define     mem(f,x)    memset(f , x , sizeof(f))
#define        sz(x)    (int)(x).size()
#define  __lcm(a, b)    (1ll * ((a) / __gcd((a), (b))) * (b))
#define          mxx    *max_element
#define          mnn    *min_element
#define    cntbit(x)    __builtin_popcountll(x)
#define       len(x)    (int)(x.length())
 
const int N = 3e5 + 10;
struct segtree{
    vector <int> seg;
    void ass(int n) {
        seg.assign(n * 4 + 100, 0);
    }
 
    void upd(int id, int l, int r, int p, int v) {
        if (l > p || r < p)
            return;
 
        seg[id] = max(seg[id], v);
        if (l == r)
            return;
 
        int m = (l + r) / 2;
        upd(id * 2, l, m, p, v);
        upd(id * 2 + 1, m + 1, r, p, v);
    }
 
    int get(int id, int l, int r, int u, int v) {
        if (r < u || l > v || u > v)
            return 0;
 
        if (l >= u && r <= v)
            return seg[id];
 
        int m = (l + r) / 2;
        return max(get(id * 2, l, m, u, v), get(id * 2 + 1, m + 1, r, u, v));
    }
};
 
segtree s1, s2;
map <int, int> mp1, mp2;
pair <int, int> best;
int n, sz;
 
void add(int u, int v) {
    int fi = s2.get(1, 1, sz, 1, mp2[v] - 1);
    if (fi > u) {
        best = max(best, {fi, v});
    }
  
    int se = s1.get(1, 1, sz, 1, mp1[u] - 1);
    if (se > v) {
        best = max(best, {u, se});
    }
 
    s1.upd(1, 1, sz, mp1[u], v);
    s2.upd(1, 1, sz, mp2[v], u);
}
 
ll solve() {
    best.f = best.s = 0;
    cin >> n;
    sz = n + 10;
    s1.ass(n + 10);
    s2.ass(n + 10);
 
    vector < vector <int>> v(n);
    for (auto &x : v) {
        x.resize(3);
        cin >> x[0] >> x[1] >> x[2];
        mp1[x[1]];
        mp2[x[2]];
    }
 
    int t1 = 1, t2 = 1;
    for (auto &x : mp1) {
        x.s = t1++;
    }
 
    for (auto &x : mp2) {
        x.s = t2++;
    }
 
    sort(all(v));
    int j = 0, ans = -1;
 
    for (int i = 0; i < n; i++) {
        while (v[j][0] < v[i][0]) {
            add(v[j][1], v[j][2]);
            j++;
        }
 
        if (best.f > v[i][1] && best.s > v[i][2]) {
            ans = max(ans, best.f + best.s + v[i][0]);
        }
    }
 
    return ans;
}
 
int main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
 
    int t = 1;
    //cin >> t;
    while (t--) {
        cout << solve() << '\n';
    }
 
    return 0;
}
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