Submission #967659

#TimeUsernameProblemLanguageResultExecution timeMemory
967659parlimoosNaan (JOI19_naan)C++14
29 / 100
26 ms12612 KiB
//Be Name KHODA
#pragma GCC optimize("Ofast")
#include<bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef long double ld;
#define pb push_back
#define pp pop_back
#define lb lower_bound
#define ub upper_bound
#define arr(x) array<int , x>
#define endl '\n'

int n , l;
int mat[2000][2000];
vector<arr(2)> pts[2000] , o;
vector<int> ord;
bool use[2000];

bool cmpKsr(arr(2) &a , arr(2) &b){
    return ((1ll * a[0] * 1ll * b[1]) < (1ll * a[1] * 1ll * b[0]));
}

int main(){
    ios::sync_with_stdio(0);
    cin.tie(0);

    cin >> n >> l;
    for(int i = 0 ; i < n ; i++){
        for(int j = 0 ; j < l ; j++){
            cin >> mat[i][j];
            mat[i][j] *= n;
        }
    }
    for(int i = 0 ; i < n ; i++){
        ll sm = 0 , now = 0;
        for(int j = 0 ; j < l ; j++) sm += 1ll * mat[i][j];
        sm /= 1ll * n;
        int tn = 1;
        for(int j = 0 ; j < l ; j++){
            while(now + (1ll * mat[i][j]) >= ((1ll * tn) * sm)){
                arr(2) d = {0 , 0};
                d[0] = int(((1ll * tn) * sm - now)) , d[1] = mat[i][j];
                d[0] += (j) * d[1];
                pts[i].pb(d) , tn++;
            }
            now += (1ll * mat[i][j]);
        }
    }

    for(int i = 0 ; i < n ; i++){
        arr(2) pt = {-1 , -1};
        int inx = -1;
        for(int j = 0 ; j < n ; j++){
            if(use[j]) continue;
            if(pt[0] == -1 or cmpKsr(pts[j][i] , pt)) pt = pts[j][i] , inx = j;
        }
        o.pb(pt) , use[inx] = 1 , ord.pb(inx);
    }
    for(int i = 1 ; i < n ; i++) cout << o[i - 1][0] << " " << o[i - 1][1] << endl;
    for(int i = 0 ; i < n ; i++) cout << ord[i] + 1 << " ";
}
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