Submission #966634

#	Time	Username	Problem	Language	Result	Execution time	Memory
966634		angella	Misspelling (JOI22_misspelling)	C++17	100 / 100	392 ms	324396 KiB

misspelling

/*
    IN THE NAME OF GOD
*/
#include <bits/stdc++.h>

// #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
// #pragma GCC optimize("O3")
// #pragma GCC optimize("unroll-loops")

using namespace std;

typedef long long ll;
typedef pair<ll, ll> pll;
typedef pair<int, int> pii;
typedef long double ld;

#define F                                      first
#define S                                      second
#define Mp                                     make_pair
#define pb                                     push_back
#define pf                                     push_front
#define size(x)                                ((ll)x.size())
#define all(x)                                 (x).begin(),(x).end()
#define kill(x)		                           cout << x << '\n', exit(0);
#define fuck(x)                                cout << "(" << #x << " , " << x << ")" << endl
#define endl                                   '\n'

const int N = 5e5+23, lg = 18;
ll Mod = 1e9+7; //998244353;

inline ll MOD(ll a, ll mod=Mod) {a%=mod; (a<0)&&(a+=mod); return a;}
inline ll poww(ll a, ll b, ll mod=Mod) {
    ll ans = 1;
    a=MOD(a, mod);
    while (b) {
        if (b & 1) ans = MOD(ans*a, mod);
        b >>= 1;
        a = MOD(a*a, mod);
    }
    return ans;
}

ll n, m, a[N], rmn[N], rmx[N], dp[27][N], pr[27][N], pr2[27][N];
int main () {
	ios_base::sync_with_stdio(false), cin.tie(0);

	cin>>n>>m;
    for(ll v,u,i=1; i<=m; i++) {
        cin>>v>>u;
        if(v<u) rmx[v] = max(rmx[v], u);
        else rmn[u] = max(rmn[u], v);
    }

    vector<int> smn={1}, smx={1};
    for(int i=1; i<=26; i++) dp[i][1]=pr2[i][1]=1, pr[i][1]=i;
    

    for(int i=2; i<=n; i++) {
        while(size(smx)>0&&rmx[smx.back()]<i) smx.pop_back();
        while(size(smn)>0&&rmn[smn.back()]<i) smn.pop_back();
        int mx=(size(smx)==0?0:smx.back());
        int mn=(size(smn)==0?0:smn.back());
        if(mn >= mx) {
            for(int j=1; j<=26; j++) {
dp[j][i] = MOD(pr[26][i-1]-pr[26][mn]-(pr2[j][i-1]-pr2[j][mn])+
pr[26][mn]-pr[26][mx]-(pr[j][mn]-pr[j][mx]));
            }
        } else {
            for(int j=1; j<=26; j++) {
dp[j][i] = MOD(pr[26][i-1]-pr[26][mx]-(pr2[j][i-1]-pr2[j][mx])+
(pr[j-1][mx]-pr[j-1][mn]));
            }
        }
        for(int j=1; j<=26; j++) {
            pr2[j][i] = MOD(pr2[j][i-1] + dp[j][i]);
            pr[j][i] = MOD(pr2[j][i] + pr[j-1][i]);
        }
        while(size(smx)>0&&rmx[smx.back()]<=rmx[i]) smx.pop_back();
        smx.pb(i);
        while(size(smn)>0&&rmn[smn.back()]<=rmn[i]) smn.pop_back();
        smn.pb(i);
    }

    cout<<pr[26][n]<<endl;

	return 0;
}

• Subtask 1: 8 / 8
• Subtask 2: 20 / 20
• Subtask 3: 29 / 29
• Subtask 4: 32 / 32
• Subtask 5: 11 / 11