이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<ll, ll> pll;
#define fastio ios::sync_with_stdio(false), cin.tie(0)
#pragma GCC optimize("Ofast,unroll-loops")
#define pb push_back
#define eb emplace_back
#define f first
#define s second
// #define int long long
#define lowbit(x) x&-x
namespace{
const int maxn = 5000 + 5;
int a[maxn][maxn], dp[maxn][maxn], h[maxn], c[maxn], mx[maxn * 2], st[maxn * 2];
int n, m, d;
int read() {
int x = 0, w = 1;
char ch = 0;
while (ch < '0' || ch > '9') { // ch 不是数字时
if (ch == '-') w = -1; // 判断是否为负
ch = getchar(); // 继续读入
}
while (ch >= '0' && ch <= '9') { // ch 是数字时
x = x * 10 + (ch - '0');
ch = getchar(); // 继续读入
}
return x * w; // 数字 * 正负号 = 实际数值
}
void main1(void){
fastio;
n = read(), m = read(), d = read();
for(int i = 0; i < n; i++){
int x = read(), y = read();
h[x] = 1;
c[y] = 1;
}
for(int i = 0; i < m; i++){
int x = read(), y = read();
a[x][y] = 1;
}
auto cal = [&](int x, int y) -> int {
if(x <= 0 || y <= 0) return 0;
return (x + y) * d - x * y;
};
int ans = 0;
for(int j = 2 * d - 1; j >= 0; j--){
int tj = j;
if(j >= d) j -= d;
if(c[j]){
j = tj;
continue;
}
for(int i = 0; i < d; i++){
if(h[i] || a[i][j]) continue;
dp[i][j] = dp[i][(j + 1) % d] + 1;
}
// if(j >= d){
// j = tj;
// continue;
// }
int top = 0;
for(int i = 0; i < 2 * d; i++){
while(top){
int cur = st[top];
if(dp[cur % d][j] <= dp[i % d][j]) break;
int id = cur % d; top--;
ans = max(ans, cal(dp[id][j], mx[cur] + (i - cur) - 1));
}
mx[i] = (top ? i - st[top] : i + 1);
st[++top] = i;
}
while(top){
int cur = st[top];
ans = max(ans, cal(dp[cur % d][j], mx[cur] + 2 * d - cur - 1));
top--;
}
j = tj;
}
ans = d * d - ans;
int cur = 0;
for(int i = d - 1; i >= 0; i--){
if(h[i]){
cur = i + 1;
break;
}
}
int tmp = d;
for(int i = 0; i < d; i++){
tmp = min(tmp, cur);
cur = (h[i] ? d : cur - 1);
}
cur = 0;
for(int i = d - 1; i >= 0; i--){
if(c[i]){
cur = i + 1;
break;
}
}
for(int i = 0; i < d; i++){
tmp = min(tmp, cur);
cur = (c[i] ? d : cur - 1);
}
ans = min(ans, d * tmp);
cout<<ans<<"\n";
}
}
int main(){
main1();
}
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