이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
void main_program();
signed main(){
ios_base::sync_with_stdio(0); cin.tie(0);
main_program();
}
const int inf = 2e9;
struct Segtree {
vector<int> tree;
int _n;
Segtree() {}
Segtree(int N): tree(4 * N, -inf), _n(N) {}
void update(int pos, int val){
update(1, 0, _n - 1, pos, val);
}
void update(int i, int l, int r, int pos, int val){
if (l == pos && r == pos){
tree[i] = val;
return;
}
int mid = (l + r) >> 1;
if (pos <= mid) update(i<<1, l, mid, pos, val);
else update(i<<1|1, mid+1, r, pos, val);
tree[i] = max(tree[i<<1], tree[i<<1|1]);
}
int get(int tl, int tr){
return get(1, 0, _n - 1, tl, tr);
}
int get(int i, int l, int r, int tl, int tr){
if (tl <= l && r <= tr) return tree[i];
if (tl > r || tr < l) return -inf;
int mid = (l + r) >> 1;
int resl = get(i<<1, l, mid, tl, tr);
int resr = get(i<<1|1, mid+1, r, tl, tr);
return max(resl, resr);
}
};
int n;
vector<int> X, E;
vector<int> order, pos;
void main_program(){
cin >> n;
X.resize(n);
E.resize(n);
order.resize(n);
pos.resize(n);
for (int i = 0; i < n; i++){
cin >> X[i] >> E[i];
}
iota(order.begin(), order.end(), 0);
sort(order.begin(), order.end(), [&](int x, int y){
return X[x] < X[y];
});
for (int i = 0; i < n; i++) pos[order[i]] = i;
vector<int> vec(n);
iota(vec.begin(), vec.end(), 0);
sort(vec.begin(), vec.end(), [&](int x, int y){
return E[x] > E[y];
});
int res = 0;
Segtree st_delta(n), st_sum(n);
for (auto idx: vec){
bool alr = false;
if (st_delta.get(pos[idx], n-1) >= E[idx] - X[idx]) alr = true;
if (st_sum.get(0, pos[idx]) >= E[idx] + X[idx]) alr = true;
if (alr) continue;
res++;
st_delta.update(pos[idx], E[idx] - X[idx]);
st_sum.update(pos[idx], E[idx] + X[idx]);
}
cout << res << "\n";
}
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