이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <iostream>
#include <vector>
#include <algorithm>
#include <cassert>
#include <numeric>
using namespace std;
using ll = long long;
#define int ll
#define vi vector<int>
#define fore(i, a, b) for(int i=a; i<b; ++i)
#define sz(x) (int)x.size()
#define all(x) x.begin(), x.end()
#define pb push_back
const int N = 1010;
vi adj[N];
int adjM[N][N];
bool vis[N];
vi list;
void dfs(int i){
    vis[i] = 1;
    list.pb(i);
    for(int v : adj[i]){
        if(vis[v]) continue;
        dfs(v);
    }
}
signed main(){
    int n, m;
    cin >> n >> m;
    fore(i, 0, m){
        int u, v;
        cin >> u >> v;
        adj[u].pb(v);
        adj[v].pb(u);
        adjM[u][v] = adjM[v][u] = 1;
    }
    // at most two complete components
    bool ok = 1;
    int cnt = 0;
    fore(i, 1, n+1){
        if(vis[i]) continue;
        list.clear();
        cnt++;
        dfs(i);
        fore(j, 0, sz(list)){
            fore(k, j+1, sz(list)){
                ok &= adjM[list[j]][list[k]];
            }
        }
    }
    if(ok && cnt <= 2){
        cout << "DA";
    } else {
        cout << "NE";
    }
    cout << endl;
}
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