Submission #962407

#TimeUsernameProblemLanguageResultExecution timeMemory
962407GrindMachineIdeal city (IOI12_city)C++17
32 / 100
1054 ms4700 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* */ const int MOD = 1e9; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; vector<int> dr = {0,1}; vector<int> dc = {1,0}; vector<pll> adj1[N]; int DistanceSum(int n, int *X, int *Y) { vector<pll> a(n); rep(i,n) a[i] = {X[i],Y[i]}; sort(all(a)); int ptr = 0; rep(i,n){ auto [r1,c1] = a[i]; rep(dir,2){ ll r2 = r1+dr[dir], c2 = c1+dc[dir]; pll px = {r2,c2}; if(!binary_search(all(a),px)) conts; ll j = lower_bound(all(a),px)-a.begin(); adj1[i].pb({j,ptr}), adj1[j].pb({i,ptr}); ptr++; } } vector<bool> vis(n); ll ans = 0; rep(i,n){ queue<pll> q; fill(all(vis),0); q.push({i,0}); vis[i] = 1; while(!q.empty()){ auto [u,d] = q.front(); q.pop(); if(u > i){ ans += d; ans %= MOD; } for(auto [v,id] : adj1[u]){ if(vis[v]) conts; q.push({v,d+1}); vis[v] = 1; } } } return ans; }
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