Submission #96142

#TimeUsernameProblemLanguageResultExecution timeMemory
96142SpeedOfMagicSequence (BOI14_sequence)C++17
0 / 100
278 ms22204 KiB
/** MIT License Copyright (c) 2018-2019(!) Vasilyev Daniil **/ #include <bits/stdc++.h> using namespace std; template<typename T> using v = vector<T>; //#define int long long typedef long double ld; typedef string str; typedef vector<int> vint; #define rep(a, l, r) for(int a = (l); a < (r); a++) #define pb push_back #define fs first #define sc second #define sz(a) ((int) a.size()) const long long inf = 4611686018427387903; //2^62 - 1 const long double EPS = 1e-9; #if 0 //FileIO const string fileName = ""; ifstream fin ((fileName == "" ? "input.txt" : fileName + ".in" )); ofstream fout((fileName == "" ? "output.txt" : fileName + ".out")); #define get fin >> #define put fout << #else #define get cin >> #define put cout << #endif #define eol put endl void read() {} template<typename Arg,typename... Args> void read (Arg& arg,Args&... args){get (arg) ;read(args...) ;} void print(){} template<typename Arg,typename... Args> void print(Arg arg,Args... args){put (arg)<<" ";print(args...);} int getInt(){int a; get a; return a;} //code starts here const int M = 1000001; char need[M][10]; int modsMin[10][7], modsMax[10][7]; void run() { rep(i, 0, M) rep(j, 0, 10) need[i][j] = 1; rep(d, 0, 10) rep(i, 0, 7) { modsMin[d][i] = 1000000000; modsMax[d][i] = -1; } int k; get k; rep(i, 0, k) { int d; get d; int cur = 10; rep(j, 0, 7) { modsMin[d][j] = min(modsMin[d][j], i % cur); modsMax[d][j] = max(modsMax[d][j], i % cur); cur *= 10; } } rep(d, 0, 10) { int cur = d; int tot = 10; rep(i, 0, 7) { if (modsMin[d][i] == 1000000000) { rep(j, 0, M) need[j][d] = 0; break; } //modsMin[d][i] + x = 1000...0 int l1 = (cur - modsMin[d][i] + tot) % tot, l2 = (cur - modsMax[d][i] + tot) % tot; int r1 = (l1 + tot / 10 - 1) % tot, r2 = (l2 + tot / 10 - 1) % tot; vint raw; for (int j = l1; j != r1; j = (j + 1) % tot) raw.pb(j); raw.pb(r1); vint pos; for (int j : raw) if ((l2 <= r2 && l2 <= j && j <= r2) || (l2 > r2 && (l2 <= j || j <= r2))) pos.pb(j); int c = (d == 0) * tot; while (c < M) { for (int j : pos) if (j + c < M) need[j + c][d] = 0; c += tot; } tot *= 10; cur *= 10; } } long long ans = inf; rep(i, 1, 900001) { long long pans = i; long long num = 0; rep(j, 1, 10) if (need[i][j]) { num = num * 10 + j; if (need[i][0]) { need[i][0] = 0; num *= 10; } } if (need[i][0]) num = 10; pans += num * 1000000; ans = min(ans, pans); } put ans; } signed main() {srand(time(0)); ios::sync_with_stdio(0); cin.tie(0); put fixed << setprecision(12); run(); return 0;}
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