Submission #960817

#	Time	Username	Problem	Language	Result	Execution time	Memory
960817		AlperenT_	Koala Game (APIO17_koala)	C++14	47 / 100	43 ms	736 KiB

koala

#include "koala.h"
#include <bits/stdc++.h>

#pragma GCC optimize("O3,unroll-loops")
#define pb push_back
#define F first
#define S second 
#define ld long double
#define all(a) a.begin(),a.end()
#define pii pair <int,int>
#define sz(v) (int)v.size()
#define rep(i , a , b) for(int i=a;i <= (b);i++)
#define per(i , a , b) for(int i=a;i >= (b);i--)
#define deb(x) cout <<#x << " : " << x << "\n" ;
using namespace std ;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int maxn = 5e5+10 , maxk = 1e4, sq = 1e5 , lg = 19,  inf = 1e9+10 , mod = 31607;
int B[maxn] , R[maxn] ;
int minValue(int N, int W) {
    int a[N] , b[N] ;
    rep(i , 0 , N-2){
        a[i] =0 ;
    }
    a[N-1] = 1;
    playRound(a,b) ;
    rep(i , 0 , N-2){
        if(b[i] == 0)return i ;
    }
    return N-1 ; 
}

int maxValue(int n, int w) {
    vector <int> vec;
    rep(i , 0 , n-1)vec.pb(i) ;
    while(sz(vec)!=1){
        int a[n] , b[n] ;
        int x =min(13 ,w/sz(vec)) ;
        rep(i ,0  ,n-1)a[i] = 0; 
        rep(i , 0 , sz(vec)-1){
            a[vec[i]] = x; 
        }
        playRound(a,b) ;
        vec.clear();
        rep(i , 0 , n-1)if(a[i] > 0 && b[i] > a[i])vec.pb(i) ;
    }
    return vec[0];
}
int greaterValue(int n, int W){
	int low=1,high=min(10,W/2);
	while(low<=high){
		int mid=(low+high)/2;
		int a[n],b[n];
		for(int i=0;i<n;i++) a[i]=0;
		a[0]=a[1]=mid;
		playRound(a,b);
		if(b[0]>mid&&b[1]>mid) low=mid+1;
		else if(b[0]<=mid&&b[1]<=mid) high=mid-1;
		else return (b[0]>mid?0:1);
	}
	return 0;
}
int n ; 
bool cmp1(int A ,int B){
    int a[n] , b[n];
    rep(i , 0 , n-1)a[i] =0 ;
    a[A] = 100 ;
    a[B] = 100 ;
    playRound(a,b); 
    if(b[A] > b[B])return 0 ;
    return 1 ;  
}
vector <int> mrg(vector <int> vec){
    if(sz(vec)==1)return vec;
    int mid = (sz(vec))/2 ;
    vector <int> a, b; 
    rep(i, 0 , mid-1){
        a.pb(vec[i]) ;
    }
    rep(i , mid , sz(vec)-1){
        b.pb(vec[i]) ;
    }
    a = mrg(a) ;
    b = mrg(b);
    vec.clear() ;
    int i1 =0 , i2= 0 ;
    while(i1 < sz(a) || i2 < sz(b)){
        if(i1 < sz(a) && (i2==sz(b) || cmp1(a[i1] , b[i2]) == 1)){
            vec.pb(a[i1]);i1++;
        }else{
            vec.pb(b[i2]);i2++;
        }
    }
    return vec;
}

void allValues(int N, int W, int *p) {
    n  = N ;
    if (W == 2*N) {
        vector <int> vec; 
        rep(i , 0 , n-1)vec.pb(i) ;
        vec= mrg(vec) ;
        rep(i , 0 ,n-1){
            p[vec[i]]=i+1 ; 
        }
    } else {
        // TODO: Implement Subtask 5 solution here.
        // You may leave this block unmodified if you are not attempting this
        // subtask.
    }
}

• Subtask 1: 4 / 4
• Subtask 2: 15 / 15
• Subtask 3: 18 / 18
• Subtask 4: 10 / 10
• Subtask 5: 0 / 53