제출 #960800

#제출 시각아이디문제언어결과실행 시간메모리
960800Whisper수열 (APIO14_sequence)C++17
71 / 100
70 ms131072 KiB
#include <bits/stdc++.h> #pragma GCC optmize("Ofast") using namespace std; using ll = long long; #define int long long #define FOR(i, a, b) for (int i = a; i <= b; i++) #define FORD(i, a, b) for (int i = b; i >= a; i --) #define REP(i, n) for (int i = 0; i < n; ++i) #define REPD(i, n) for (int i = n - 1; i >= 0; --i) #define MASK(i) (1LL << (i)) #define BIT(x, i) (((x) >> (i)) & 1) constexpr ll LINF = (1ll << 60); constexpr int INF = (1ll << 30); constexpr int Mod = 1e9 + 7; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); void setupIO(){ #define name "Whisper" //Phu Trong from Nguyen Tat Thanh High School for gifted student srand(time(NULL)); cin.tie(nullptr)->sync_with_stdio(false); cout.tie(nullptr); //freopen(name".inp", "r", stdin); //freopen(name".out", "w", stdout); cout << fixed << setprecision(10); } template <class X, class Y> bool minimize(X &x, const Y &y){ X eps = 1e-9; if (x > y + eps) {x = y; return 1;} return 0; } template <class X, class Y> bool maximize(X &x, const Y &y){ X eps = 1e-9; if (x + eps < y) {x = y; return 1;} return 0; } int nArr, nGroup; const int MAX = 1e5 + 5; int a[MAX]; int dp[MAX][2]; int opt[MAX][205]; int s[MAX]; struct Line { ll a, b, id; Line (ll _a = 0, ll _b = 0, ll _id = -1) { a = _a; b = _b; id = _id; }; ll cal(ll x) { return a * x + b; } long double cross(Line o) { return (long double) (b - o.b) / (long double) (o.a - a); } }; struct CHT { deque <Line> q; void addLine(Line nLine) { // need to change when a is increasing or decreasing while (q.size() >= 2 && (q.back().cross(nLine) <= q.back().cross(q[q.size() - 2]) || (q.back().a == nLine.a && q.back().b <= nLine.b))) q.pop_back(); q.push_back(nLine); } pair <ll, int> query(ll x) { while (q.size() >= 2 && q[0].cal(x) <= q[1].cal(x)) q.pop_front(); return {q[0].cal(x), q[0].id}; } }; void Whisper(){ cin >> nArr >> nGroup; ++nGroup; for (int i = 1; i <= nArr; ++i) cin >> a[i], s[i] = s[i - 1] + a[i]; //s[nArr] * s[i] - s[nArr] * s[j] - s[i] * s[i] + s[i] * s[j] //using s(j) as x we have equation //s(j) * x + - s(nArr) * s(j) - s(i) * s(i) + s(nArr) * s(i) + dp(j, k - 1) for (int k = 1; k <= nGroup; ++k){ CHT cht; cht.addLine(Line(0, 0, 0)); for (int i = 1; i <= nArr; ++i){ pair<int, int> ret = cht.query(s[i]); dp[i][1] = ret.first + s[nArr] * s[i] - s[i] * s[i]; opt[i][k] = ret.second; cht.addLine(Line(s[i], -s[i] * s[nArr] + dp[i][0], i)); } for (int i = 1; i <= nArr; ++i){ dp[i][0] = dp[i][1]; } } cout << dp[nArr][0] << '\n'; vector<int> ans; int current = nArr; while(nGroup > 0){ if (current != nArr) ans.push_back(current); current = opt[current][nGroup]; nGroup--; } reverse(ans.begin(), ans.end()); for (int&v : ans) cout << v << " "; } signed main(){ setupIO(); int Test = 1; // cin >> Test; for ( int i = 1 ; i <= Test ; i++ ){ Whisper(); if (i < Test) cout << '\n'; } }

컴파일 시 표준 에러 (stderr) 메시지

sequence.cpp:2: warning: ignoring '#pragma GCC optmize' [-Wunknown-pragmas]
    2 | #pragma GCC optmize("Ofast")
      |
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