제출 #960791

#제출 시각아이디문제언어결과실행 시간메모리
960791Whisper수열 (APIO14_sequence)C++17
71 / 100
55 ms131072 KiB
#include <bits/stdc++.h> using namespace std; using ll = long long; #define int long long #define FOR(i, a, b) for (int i = a; i <= b; i++) #define FORD(i, a, b) for (int i = b; i >= a; i --) #define REP(i, n) for (int i = 0; i < n; ++i) #define REPD(i, n) for (int i = n - 1; i >= 0; --i) #define MASK(i) (1LL << (i)) #define BIT(x, i) (((x) >> (i)) & 1) constexpr ll LINF = (1ll << 60); constexpr int INF = (1ll << 30); constexpr int Mod = 1e9 + 7; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); void setupIO(){ #define name "Whisper" //Phu Trong from Nguyen Tat Thanh High School for gifted student srand(time(NULL)); cin.tie(nullptr)->sync_with_stdio(false); cout.tie(nullptr); //freopen(name".inp", "r", stdin); //freopen(name".out", "w", stdout); cout << fixed << setprecision(10); } template <class X, class Y> bool minimize(X &x, const Y &y){ X eps = 1e-9; if (x > y + eps) {x = y; return 1;} return 0; } template <class X, class Y> bool maximize(X &x, const Y &y){ X eps = 1e-9; if (x + eps < y) {x = y; return 1;} return 0; } int nArr, nGroup; const int MAX = 1e5 + 5; int a[MAX]; int dp[MAX][202]; int opt[MAX][202]; int s[MAX]; struct Line{ int a, b, id; Line(): a(0), b(0), id(-1){} Line(int _a, int _b, int _id): a(_a), b(_b), id(_id){} int f(int x){ return a * x + b; } double cross(Line o){ return (double) (b - o.b) / (double)(o.a - a); } }; //slope is increasing and query is also increasing struct CHT{ deque<Line> q; bool bad(Line a, Line b, Line c){ return a.cross(c) <= a.cross(b); } void addLine(Line line){ while (q.size() >= 2 && (bad(q.end()[-1], q.end()[-2], line) || (q.back().a == line.a && q.back().b <= line.b))) q.pop_back(); q.push_back(line); } pair<int, int> query(int x){ while (q.size() >= 2 && q[0].f(x) <= q[1].f(x)) q.pop_front(); return make_pair(q[0].f(x), q[0].id); } }; void Whisper(){ cin >> nArr >> nGroup; ++nGroup; for (int i = 1; i <= nArr; ++i) cin >> a[i], s[i] = s[i - 1] + a[i]; for (int i = 1; i <= nArr; ++i) dp[i][1] = s[i] * (s[nArr] - s[i]); //s[nArr] * s[i] - s[nArr] * s[j] - s[i] * s[i] + s[i] * s[j] //using s(j) as x we have equation //s(j) * x + - s(nArr) * s(j) - s(i) * s(i) + s(nArr) * s(i) + dp(j, k - 1) for (int k = 2; k <= nGroup; ++k){ CHT cht; cht.addLine(Line(0, 0, -1)); for (int i = 1; i <= nArr; ++i){ pair<int, int> ret = cht.query(s[i]); dp[i][k] = ret.first + s[nArr] * s[i] - s[i] * s[i]; opt[i][k] = ret.second; cht.addLine(Line(s[i], - s[i] * s[nArr] + dp[i][k - 1], i)); } } cout << dp[nArr][nGroup] << '\n'; vector<int> ans; int current = nArr; while(nGroup > 0){ if (current != nArr) ans.push_back(current); current = opt[current][nGroup]; nGroup--; } reverse(ans.begin(), ans.end()); for (int&v : ans) cout << v << " "; } signed main(){ setupIO(); int Test = 1; // cin >> Test; for ( int i = 1 ; i <= Test ; i++ ){ Whisper(); if (i < Test) cout << '\n'; } }
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