Submission #960257

#	Time	Username	Problem	Language	Result	Execution time	Memory
960257		ono_de206	Sjeckanje (COCI21_sjeckanje)	C++14	55 / 110	786 ms	32516 KiB

Main

#include<bits/stdc++.h>
using namespace std;

#define fast ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define in insert
#define all(x) x.begin(),x.end()
#define pb push_back
#define eb emplace_back
#define ff first
#define ss second

#define int long long

typedef long long ll;
typedef vector<int> vi;
typedef set<int> si;
typedef multiset<int> msi;
typedef pair<int, int> pii;
typedef vector<pii> vpii;
// typedef pair<int, int> P;

template<typename T, typename U>
ostream & operator << (ostream &out, const pair<T, U> &c) {
	out << c.first << ' ' << c.second;
	return out;
}

template<typename T>
ostream & operator << (ostream &out, vector<T> &v) {
	const int sz = v.size();
	for (int i = 0; i < sz; i++) {
		if (i) out << ' ';
		out << v[i];
	}
	return out;
}

template<typename T>
istream & operator >> (istream &in, vector<T> &v) {
	for (T &x : v) in >> x;
	return in;
}

template<typename T, typename U>
	istream & operator >> (istream &in, pair<T, U> &c) {
	in >> c.first;
	in >> c.second;
	return in;
}

template<typename T>
void mxx(T &a, T b){if(b > a) a = b;}
template<typename T>
void mnn(T &a, T b){if(b < a) a = b;}

const int mxn = 2e5 + 10, MXLOG = 22, mod = 1e9 + 7, P = 1181;// D = 1523, N = 2500;
const long long inf = 2e18 + 10;
int d[mxn * 4][2][2], b[mxn][2], D[mxn];

void up(int i, int x, int y) {
	b[i][0] = b[x][0];
	b[i][1] = b[y][1];
	for(int l = 0; l < 2; l++) {
		for(int r = 0; r < 2; r++) {
			d[i][l][r] = 0;
		}
	}
	for(int l = 0; l < 2; l++) {
		for(int r = 0; r < 2; r++) {
			for(int rr = 0; rr < 2; rr++) {
				for(int ll = 0; ll < 2; ll++) {
					if(ll & rr) {
						if((b[x][1] >= 0 && b[y][0] >= 0) || (b[x][1] <= 0 && b[y][0] <= 0)) {
							mxx(d[i][l][r], d[x][l][rr] + d[y][ll][r]);
						}
					} else {
						mxx(d[i][l][r], d[x][l][rr] + d[y][ll][r]);
					}
				}
			}
		}
	}
}

void build(int l, int r, int i) {
	if(l == r) {
		b[i][0] = b[i][1] = D[l];
		d[i][1][1] = abs(D[l]);
		return;
	}
	int m = (l + r) / 2;
	build(l, m, i * 2);
	build(m + 1, r, i * 2 + 1);
	up(i, i * 2, i * 2 + 1);
}

void update(int l, int r, int i, int x, int y) {
	if(l == r) {
		D[l] += y;
		b[i][0] = b[i][1] = D[l];
		d[i][1][1] = abs(D[l]);
		return;
	}
	int m = (l + r) / 2;
	if(x <= m) update(l, m, i * 2, x, y);
	else update(m + 1, r, i * 2 + 1, x, y);
	up(i, i * 2, i * 2 + 1);
}

void go() {
	int n, q;
	cin >> n >> q;
	int ls;
	cin >> ls;
	if(n == 1) {
		for(int i = 1; i <= q; i++) {
			cout << 0 << endl;
		}
		return;
	}
	for(int i = 2; i <= n; i++) {
		int x;
		cin >> x;
		D[i] = x - ls;
		ls = x;
	}
	build(2, n, 1);
	while(q--) {
		int l, r, x;
		cin >> l >> r >> x;
		if(l > 1) update(2, n, 1, l, x);
		if(r < n) update(2, n, 1, r + 1, -x);
		cout << d[1][1][1] << endl;
	}
}

signed main() {
	fast;
	int t = 1;
	// cin >> t;
	while(t--) {
		go();
	}
	return 0;
}

• Subtask 1: 15 / 15
• Subtask 2: 40 / 40
• Subtask 3: 0 / 55