답안 #960017

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
960017 2024-04-09T13:36:10 Z 8pete8 팀들 (IOI15_teams) C++17
0 / 100
4000 ms 9664 KB
#include "teams.h"
#include<iostream>
#include<stack>
#include<map>
#include<vector>
#include<string>
#include<unordered_map>
#include <queue>
#include<cstring>
#include<limits.h>
#include <cassert>
#include<cmath>
#include<set>
#include<algorithm>
#include <iomanip>
#include<numeric> //gcd(a,b)
#include<bitset>
using namespace std;
#define ll long long
#define f first
#define endl "\n"
#define s second
#define pii pair<int,int>
#define ppii pair<int,pii>
#define vi vector<int>
#define pb push_back
#define all(x) x.begin(),x.end()
#define rall(x) x.rbegin(),x.rend()
#define F(n) for(int i=0;i<n;i++)
#define lb lower_bound
#define ub upper_bound
#define fastio ios::sync_with_stdio(false);cin.tie(NULL);
#pragma GCC optimize ("03,unroll-loops")
using namespace std;
//#define double long double
vector<pii>v;
int n;
bool cmp(pii a,pii b){
	if(a.s==b.s)return a.f>b.f;
	return a.s<b.s;
}
void init(int N, int A[], int B[]){
	n=N;
	for(int i=0;i<n;i++)v.pb({A[i],B[i]});
	sort(all(v),cmp);
}
int can(int m, int k[]){
	multiset<pii>st;
	for(int i=0;i<m;i++)st.insert({k[i],k[i]});
	for(int i=0;i<n;i++){
		auto it=st.lb({v[i].f,0});
		if(it==st.end())continue;
		pii a=(*it);
		st.erase(it);
		a.s--;
		if(a.s)st.insert(a);
	}
	return st.empty();
}/*
int32_t main(){
	int n;cin>>n;
	int a[n],b[n];
	for(int i=0;i<n;i++)cin>>a[i]>>b[i];
	init(n,a,b);
	int q;cin>>q;
	while(q--){
		int m;cin>>m;
		int k[m];
		for(int i=0;i<m;i++)cin>>k[i];
		cout<<can(m,k)<<'\n';
	}
}*/

/*
we can greedy?
sort all pair(a,b) by b
then for each k 1->m
we can find the first k[i] range that cover k[i]
we can keep doing this?
this will be (s*n) where each m in each qry can be at most n

if this work->we can do sqrt decomp?
*/
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 344 KB Output is correct
2 Correct 0 ms 348 KB Output is correct
3 Correct 1 ms 348 KB Output is correct
4 Correct 1 ms 348 KB Output is correct
5 Incorrect 0 ms 348 KB Output isn't correct
6 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 16 ms 2260 KB Output is correct
2 Correct 15 ms 2260 KB Output is correct
3 Incorrect 17 ms 2256 KB Output isn't correct
4 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 229 ms 2372 KB Output is correct
2 Correct 256 ms 2260 KB Output is correct
3 Execution timed out 4057 ms 2260 KB Time limit exceeded
4 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 1018 ms 9664 KB Output is correct
2 Correct 1179 ms 9220 KB Output is correct
3 Execution timed out 4051 ms 8808 KB Time limit exceeded
4 Halted 0 ms 0 KB -