Submission #959432

#	Time	Username	Problem	Language	Result	Execution time	Memory
959432		Alkaser_ID	Financial Report (JOI21_financial)	C++17	5 / 100	145 ms	21496 KiB

Main

#include <iostream>
#include <algorithm>
#include <vector>
#include <map>
#include <set>
#include <queue>
using namespace std;
typedef long long ll;
// second mod 998244353
const ll N = 3e5 + 5;

ll a[N], b[N];
struct order
{
    ll i, v;
};
bool cmp(order x, order y) {
    if (x.v == y.v) return x.i > y.i;
    return x.v < y.v;
}
ll seg[10 * N];
inline void update(ll node, ll l, ll r, ll ind, ll vl) {
    if (l == r) return void(seg[node] = vl);
    ll mid = (l + r) / 2;
    if (ind <= mid) 
        update(node * 2, l, mid, ind, vl);
    else update(node * 2 + 1, mid + 1, r, ind, vl);
    seg[node] = max(seg[node * 2], seg[node * 2 + 1]);
}
inline void del(ll node, ll l, ll r, ll ind) {
    if (l == r) return void(seg[node] = 0);
    ll mid = (l + r) / 2;
    if (ind <= mid)
        del(node * 2, l, mid, ind);
    else del(node * 2 + 1, mid + 1, r, ind);
    seg[node] = max(seg[node * 2], seg[node * 2 + 1]);
}
inline ll get(ll node, ll l, ll r, ll lx, ll rx) {
    if (l >= lx && r <= rx) return seg[node];
    if (l > rx || r < lx) return 0;
    ll mid = (l + r) / 2;
    ll r1 = get(node * 2, l, mid, lx, rx);
    ll r2 = get(node * 2 + 1, mid + 1, r, lx, rx);
    return max(r1, r2);
}
int main() {
    ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
    ll n, d; cin >> n >> d;
    vector<order> v;
    for (ll i = 1; i <= n; ++i) {
        cin >> a[i];
        order nw;
        nw.v = a[i]; nw.i = i;
        v.push_back(nw);
    }
    sort(v.begin(), v.end(), cmp);
    ll MX = n + 2;
    for (ll i = 0; i < n; ++i) {
        a[v[i].i] = i + 1;
    }
    ll res = 0; ++MX;
    for (ll i = n; i > 0; --i) {
        if (i + d < n) 
            del(1, 1, MX, a[i + d + 1]);
        ll x = get(1, 1, MX, a[i], MX);
        ++x;
        res = max(res, x);
        update(1, 1, MX, a[i], x);
    }
    cout << res;
}

• Subtask 1: 0 / 14
• Subtask 2: 0 / 14
• Subtask 3: 0 / 20
• Subtask 4: 0 / 12
• Subtask 5: 5 / 5
• Subtask 6: 0 / 35