oj.uz

답안 #958881

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
958881 2024-04-07T02:18:10 Z Pring 구경하기 (JOI13_watching) C++17
50 / 100
 1000 ms 31412 KB 
#include <bits/stdc++.h>
#pragma GCC optimize("O3","unroll-loops")
#pragma GCC target("avx","popcnt","sse4","abm")
using namespace std;

#ifdef MIKU
string dbmc = "\033[1;38;2;57;197;187m", dbrs = "\033[0m";
#define debug(x...) cout << dbmc << "[" << #x << "]: ", dout(x)
void dout() { cout << dbrs << endl; }
template <typename T, typename ...U>
void dout(T t, U ...u) { cout << t << (sizeof...(u) ? ", " : ""); dout(u...); }
#else
#define debug(...) 39
#endif

#define int long long
#define fs first
#define sc second
#define mp make_pair
#define FOR(i, j, k) for (int i = j, Z = k; i < Z; i++)
using ll = long long;
typedef pair<int, int> pii;

const int MXN = 2005, MXC = 1000000005;
int n, X, Y, a[MXN];
int dp[MXN][MXN], l[MXN], l2[MXN];
deque<pii> dq, dq2;

void PRE(int w) {
    int p = 0, pp = 0;
    FOR(i, 1, n + 1) {
        while (a[i] - a[p] >= w) p++;
        while (a[i] - a[pp] >= 2 * w) pp++;
        l[i] = p - 1;
        l2[i] = pp - 1;
    }
}

bool check(int w) {
    PRE(w);
    dp[0][0] = 0;
    FOR(j, 1, n + 1) dp[0][j] = dp[0][l2[j]] + 1;
    auto POP = [&](deque<pii> &dq, int t) -> void {
        while (dq.size() && dq.front().fs < t) dq.pop_front();
    };
    auto PUSH = [&](deque<pii> &dq, int id, int val) -> void {
        while (dq.size() && dq.back().sc >= val) dq.pop_back();
        dq.push_back(mp(id, val));
    };
    // FOR(j, 1, X + 1) {
    //     dp[j][0] = 0;
    //     dq.clear();
    //     dq2.clear();
    //     PUSH(dq, 0, dp[j - 1][0]);
    //     PUSH(dq2, 0, dp[j][0]);
    //     FOR(i, 1, n + 1) {
    //         POP(dq, l[i]);
    //         POP(dq2, l2[i]);
    //         dp[i][j] = min(dq.front().sc, dq2.front().sc + 1);
    //         PUSH(dq, i, dp[j - 1][i]);
    //         PUSH(dq2, i, dp[j][i]);
    //     }
    // }
    FOR(i, 1, X + 1) {
        dp[i][0] = 0;
        dq.clear();
        dq2.clear();
        PUSH(dq, 0, 0);
        PUSH(dq2, 0, 0);
        FOR(j, 1, n + 1) {
            POP(dq, l[j]);
            POP(dq2, l2[j]);
            dp[i][j] = min(dq.front().sc, dq2.front().sc + 1);
            PUSH(dq, j, dp[i - 1][j]);
            PUSH(dq2, j, dp[i][j]);
        }
    }
    FOR(i, 0, X + 1) if (dp[i][n] <= Y) return true;
    return false;
}

void miku() {
    cin >> n >> X >> Y;
    FOR(i, 1, n + 1) cin >> a[i];
    sort(a + 1, a + n + 1);
    n = unique(a + 1, a + n + 1) - (a + 1);
    if (X + Y >= n) {
        cout << 1 << '\n';
        return;
    }
    a[0] = -2 * MXC;
    int l = 0, r = MXC;
    while (l + 1 < r) {
        int mid = (l + r) >> 1;
        (check(mid) ? r : l) = mid;
    }
    cout << r << '\n';
}

int32_t main() {
    cin.tie(0) -> sync_with_stdio(false);
    cin.exceptions(cin.failbit);
    miku();
    return 0;
}

Subtask #1
50.0 / 50.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 348 KB Output is correct
2 Correct 0 ms 348 KB Output is correct
3 Correct 0 ms 348 KB Output is correct
4 Correct 0 ms 348 KB Output is correct
5 Correct 0 ms 348 KB Output is correct
6 Correct 1 ms 348 KB Output is correct
7 Correct 1 ms 344 KB Output is correct
8 Correct 1 ms 344 KB Output is correct
9 Correct 1 ms 2588 KB Output is correct
10 Correct 1 ms 2392 KB Output is correct
11 Correct 3 ms 2396 KB Output is correct
12 Correct 3 ms 2584 KB Output is correct
13 Correct 0 ms 348 KB Output is correct
14 Correct 1 ms 348 KB Output is correct
15 Correct 1 ms 348 KB Output is correct

Subtask #2
0 / 50.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 348 KB Output is correct
2 Correct 1 ms 348 KB Output is correct
3 Correct 1 ms 344 KB Output is correct
4 Correct 1 ms 348 KB Output is correct
5 Correct 1 ms 348 KB Output is correct
6 Correct 1 ms 348 KB Output is correct
7 Correct 12 ms 2708 KB Output is correct
8 Correct 109 ms 2648 KB Output is correct
9 Correct 604 ms 12944 KB Output is correct
10 Execution timed out 1048 ms 31412 KB Time limit exceeded
11 Halted 0 ms 0 KB -