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답안 #95852

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
95852 2019-02-03T07:24:37 Z Kastanda Potemkin cycle (CEOI15_indcyc) C++11
70 / 100
 1000 ms 1404 KB 
#include<bits/stdc++.h>
using namespace std;
const int N = 1009;
int n, m, qu[N], P[N];
bitset < N > M, S, is[N];
vector < int > Adj[N];
inline void Prnt(int fxd, int v, int u)
{
    M = S = 0;
    memset(P, 0, sizeof(P));
    for (int &w : Adj[fxd])
        M[w] = 1;
    int l = 0, r = 0;
    qu[r ++] = v;
    S[v] = 1;
    while (r - l)
    {
        int nw = qu[l ++];
        for (int &w : Adj[nw])
            if (w != fxd && !S[w] && !(M[nw] && M[w]))
            {
                S[w] = 1;
                P[w] = nw;
                if (!M[w])
                    qu[r ++] = w;
            }
    }
    if (P[u] == 0)
        return ;
    vector < int > A;
    A.push_back(fxd);
    for (; u; u = P[u])
        A.push_back(u);
    for (int i = 0; i < (int)A.size(); i++)
        for (int j = i + 2; j < (int)A.size(); j++)
            if ((i != 0 || j != (int)A.size() - 1) && is[A[i]][A[j]])
                assert(0);
    for (int a : A)
        printf("%d ", a);
    printf("\n");
    exit(0);
}
int main()
{
    scanf("%d%d", &n, &m);
    for (int i = 1; i <= m; i++)
    {
        int v, u;
        scanf("%d%d", &v, &u);
        Adj[v].push_back(u);
        Adj[u].push_back(v);
        is[v][u] = is[u][v] = 1;
    }
    for (int fxd = 1; fxd <= n; fxd ++)
        for (int v : Adj[fxd])
            for (int u : Adj[fxd])
                if (v < u && !is[v][u])
                    Prnt(fxd, v, u);
    return !printf("no\n");
}

Compilation message

indcyc.cpp: In function 'int main()':
indcyc.cpp:45:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d%d", &n, &m);
     ~~~~~^~~~~~~~~~~~~~~~
indcyc.cpp:49:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%d%d", &v, &u);
         ~~~~~^~~~~~~~~~~~~~~~

Subtask #1
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 376 KB Output is correct
2 Correct 2 ms 376 KB Output is correct
3 Correct 2 ms 376 KB Output is correct
4 Correct 2 ms 376 KB Output is correct
5 Correct 2 ms 376 KB Output is correct

Subtask #2
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 380 KB Output is correct

Subtask #3
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 376 KB Output is correct
2 Correct 2 ms 376 KB Output is correct

Subtask #4
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 380 KB Output is correct

Subtask #5
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 376 KB Output is correct
2 Correct 10 ms 380 KB Output is correct

Subtask #6
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 134 ms 504 KB Output is correct
2 Correct 3 ms 504 KB Output is correct
3 Correct 3 ms 504 KB Output is correct
4 Correct 99 ms 508 KB Output is correct

Subtask #7
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 376 KB Output is correct
2 Correct 96 ms 508 KB Output is correct

Subtask #8
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 718 ms 1056 KB Output is correct
2 Correct 99 ms 760 KB Output is correct
3 Execution timed out 1063 ms 1016 KB Time limit exceeded
4 Halted 0 ms 0 KB -

Subtask #9
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 35 ms 760 KB Output is correct
2 Execution timed out 1069 ms 760 KB Time limit exceeded

Subtask #10
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 44 ms 1300 KB Output is correct
2 Correct 306 ms 1404 KB Output is correct
3 Correct 212 ms 1144 KB Output is correct
4 Execution timed out 1069 ms 1272 KB Time limit exceeded