Submission #958297

#	Time	Username	Problem	Language	Result	Execution time	Memory
958297		Vladth11	Hamburg Steak (JOI20_hamburg)	C++14	6 / 100	3048 ms	20436 KiB

hamburg

#include <bits/stdc++.h>
#define debug(x) cerr << #x << " " << x << "\n"
#define debugs(x) cerr << #x << " " << x << " "
#pragma GCC optimize ("Ofast")
#pragma GCC target ("avx2")

#define int ll

using namespace std;
typedef long long ll;
typedef pair <ll, ll> pii;

const ll NMAX = 1000001;
const ll INF = 1e9;
const ll nrbits = 20;
const ll MOD = 998244353;

struct rect {
    int x1, y1, x2, y2;
} q[NMAX];

rect buckets[11];
int last[NMAX];

rect combine(rect a, rect b) {
    rect sol = {max(a.x1, b.x1), max(a.y1, b.y1), min(a.x2, b.x2), min(a.y2, b.y2)};
    return sol;
}

signed main() {
#ifdef HOME
    ifstream cin(".in");
    ofstream cout(".out");
#endif // HOME
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    srand(time(0));
    int n, i, k;
    cin >> n >> k;
    for(i = 1; i <= n; i++) {
        cin >> q[i].x1 >> q[i].y1 >> q[i].x2 >> q[i].y2;
    }
    while(1) {
        for(int j = 1; j <= k; j++) {
            buckets[j] = {0, 0, INF, INF};
        }
        vector <int> qq;
        for(i = 1; i <= n; i++) {
            qq.push_back(i);
        }
        random_shuffle(qq.begin(), qq.end());
        int cnt = 0;
        while(qq.size()) {
            int acum = qq.back();
            qq.pop_back();
            int oke = 0;
            int care = 0;
            for(int j = 1; j <= k; j++) {
                rect inters = combine(q[acum], buckets[j]);
                if(inters.x1 <= inters.x2 && inters.y1 <= inters.y2) {
                    care = j;
                    oke++;
                }
            }
            buckets[care] = combine(q[acum], buckets[care]);
            if(oke) cnt++;
        }
        if(cnt == n) {
            for(i = 1; i <= k; i++) {
                cout << buckets[i].x1 << " " << buckets[i].y1 << "\n";
            }
            return 0;
        }
    }
    return 0;
}

• Subtask 1: 1 / 1
• Subtask 2: 1 / 1
• Subtask 3: 3 / 3
• Subtask 4: 0 / 6
• Subtask 5: 1 / 1
• Subtask 6: 0 / 3
• Subtask 7: 0 / 6
• Subtask 8: 0 / 79