Submission #958238

#	Time	Username	Problem	Language	Result	Execution time	Memory
958238		Vladth11	Hamburg Steak (JOI20_hamburg)	C++14	2 / 100	71 ms	11856 KiB

hamburg

#include <bits/stdc++.h>
#define debug(x) cerr << #x << " " << x << "\n"
#define debugs(x) cerr << #x << " " << x << " "
#pragma GCC optimize ("Ofast")
#pragma GCC target ("avx2")
 
#define int ll
 
using namespace std;
typedef long long ll;
typedef pair <ll, ll> pii;
 
const ll NMAX = 1000001;
const ll INF = 1e9;
const ll nrbits = 20;
const ll MOD = 998244353;
 
struct rect {
    int x1, y1, x2, y2;
} q[NMAX];
 
rect buckets[11];
int last[NMAX];
 
rect combine(rect a, rect b){
    rect sol = {max(a.x1, b.x1), max(a.y1, b.y1), min(a.x2, b.x2), min(a.y2, b.y2)};
    return sol;
}
 
signed main() {
#ifdef HOME
    ifstream cin(".in");
    ofstream cout(".out");
#endif // HOME
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    int n, i, k;
    cin >> n >> k;
    queue <int> qq;
    for(i = 1; i <= n; i++) {
        cin >> q[i].x1 >> q[i].y1 >> q[i].x2 >> q[i].y2;
        qq.push(i);
    }
    for(int j = 1; j <= k; j++) {
        buckets[j] = {0, 0, INF, INF};
    }
    int cnt = 0, oho = 0;
    while(qq.size()) {
        int acum = qq.front();
        qq.pop();
            int oke = 0;
            int care = 0;
      if(last[acum] == cnt)
          oho = 1;
            for(int j = 1; j <= k; j++) {
                rect inters = combine(q[acum], buckets[j]);
                if(inters.x1 <= inters.x2 && inters.y1 <= inters.y2){
                  if(!care)  
                  care = j;
                    oke++;
                }
            }
            if(oke == 1 || (oho)){
                buckets[care] = combine(q[acum], buckets[care]);
                cnt++;
            }else{
                qq.push(acum); /// oke sigur e mai mare ca 0
            }
      	
        last[acum] = cnt;
    }
    for(i = 1; i <= k; i++){
        cout << buckets[i].x1 << " " << buckets[i].y1 << "\n";
    }
    return 0;
}

• Subtask 1: 1 / 1
• Subtask 2: 0 / 1
• Subtask 3: 0 / 3
• Subtask 4: 0 / 6
• Subtask 5: 1 / 1
• Subtask 6: 0 / 3
• Subtask 7: 0 / 6
• Subtask 8: 0 / 79