#include <bits/stdc++.h>
//#pragma GCC optimize("O3")
//#pragma GCC optimize("unroll-loops")
using namespace std;
#define int long long
#define vi vector<int>
#define vl vector<long long>
#define vii vector<pair<int,int>>
#define vll vector<pair<long long,long long>>
#define pb push_back
#define ll long long
#define ld long double
#define nl '\n'
#define boost ios::sync_with_stdio(false)
#define mp make_pair
#define se second
#define fi first
#define fore(i, y) for(int i = 0; i < y; i++)
#define forr(i,x,y) for(int i = x;i<=y;i++)
#define forn(i,y,x) for(int i = y; i >= x; i--)
#define all(v) v.begin(),v.end()
#define sz(v) (int)v.size()
#define clr(v,k) memset(v,k,sizeof(v))
#define rall(v) v.rbegin() , v.rend()
#define pii pair<int,int>
#define pll pair<ll , ll>
#define vvi vector<vi>
#define vvii vector<vii>
const ll MOD = 1e9 + 7;
const ll INF = 1e18 + 1;
ll gcd(ll a , ll b) {return b ? gcd(b , a % b) : a ;} // greatest common divisor (gcd)
ll lcm(ll a , ll b) {return a * (b / gcd(a , b));} // least common multiple (lcm)
// HERE IS THE SOLUTION
int N , K , M , O;
const int LOG = 15;
int lim;
vvii adj;
vector<vi> comb(vector<vi> a , vector<vi> b)
{
vector<vi> target(K , vi(K , INF));
fore(x , K)
{
fore(y , K)
{
fore(z , K)
{
target[x][y] = min(target[x][y] , a[x][z] + b[z][y]);
}
}
}
return target;
}
vector<vvi> tree;
void build(int node , int l , int r)
{
if(r == l + 1)
{
forr(a , l * K , l * K + K - 1)
{
for(auto [b , t] : adj[a])
{
tree[node][a%K][b%K] = min(tree[node][a%K][b%K] , t);
}
}
return ;
}
int mid = (l + r)/2;
build(2*node , l , mid);
build(2*node + 1 , mid , r);
tree[node] = comb(tree[2*node] , tree[2*node + 1]);
}
vvi query(int node , int L , int R , int l , int r)
{
if(l <= L && R <= r)
return tree[node];
int mid = (L + R)/2;
if(r <= mid)
return query(2*node , L , mid , l , r);
if(l >= mid)
return query(2*node + 1, mid , R , l, r);
return comb(query(2*node , L , mid , l , r) , query(2*node + 1 , mid , R , l , r));
}
signed main()
{
boost;
cin.tie(0);
cout.tie(0);
cin>>K>>N>>M>>O;
lim = (N+ K - 1)/K;
adj.resize(N + K + 1);
while(__builtin_popcount(lim) != 1)
{
lim++;
}
tree.assign(2*lim , vvi(K , vi(K , INF)));
fore(i , M)
{
int a , b ,t;
cin>>a>>b>>t;
adj[a].pb({b , t});
}
build(1 , 0 , lim);
while(O--)
{
int a , b;
cin>>a>>b;
if(a/K == b/K)
{
cout<<-1<<nl;
continue;
}
int ans = query(1 , 0 , lim , a/K , b/K)[a%K][b%K];
cout<<(ans >= INF ? -1 : ans)<<nl;
}
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Runtime error |
50 ms |
28824 KB |
Execution killed with signal 11 |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Runtime error |
47 ms |
27728 KB |
Execution killed with signal 11 |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Runtime error |
1 ms |
348 KB |
Execution killed with signal 11 |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Runtime error |
1 ms |
348 KB |
Execution killed with signal 11 |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Runtime error |
50 ms |
28824 KB |
Execution killed with signal 11 |
2 |
Halted |
0 ms |
0 KB |
- |