제출 #955233

#제출 시각아이디문제언어결과실행 시간메모리
955233MarwenElarbiRailway Trip 2 (JOI22_ho_t4)C++17
0 / 100
790 ms127824 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #define vi vector<int> #define ve vector #define ll long long #define vl vector<ll> #define vll vector<pair<ll,ll>> #define onbit __builtin_popcount #define ii pair<int,int> #define vvi vector<vi> #define vii vector<ii> #define gii greater<ii> #define pb push_back #define mp make_pair #define fi first #define se second #define INF 1e18 #define eps 1e-7 #define eps1 1e-2 #define optimise ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL); #define MAX_A 1e5+5 using namespace std; using namespace __gnu_pbds; template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; const ll MOD = 1e9+7; const int nax = 1e5+5; const int MAX_VAL = 1e6+1; double PI=3.14159265359; int arx[8]={1,0,0,-1,-1,-1, 1, 1}; int ary[8]={0,1,-1, 0, 1,-1,-1, 1}; void setIO(string s) { freopen((s + ".in").c_str(), "r", stdin); freopen((s + ".out").c_str(), "w", stdout); } int lg=18; ii segtree[nax*4][18]; void update(int pos,int l,int r,int idx,ii value,int level){ if(l==r){ segtree[pos][level]=value; return; } int mid=(r+l)/2; if(idx<=mid) update(pos*2+1,l,mid,idx,value,level); else update(pos*2+2,mid+1,r,idx,value,level); segtree[pos][level].fi=max(segtree[pos*2+1][level].fi,segtree[pos*2+2][level].fi); segtree[pos][level].se=min(segtree[pos*2+1][level].se,segtree[pos*2+2][level].se); //cout <<l<<" "<<r<<" "<<segtree[pos][level].fi<<" "<<segtree[pos][level].se<<endl; return; } ii query(int pos,int l,int r,int left,int right,int level){ if(l>r||l>right||r<left) return {-1e9,1e9}; if(l>=left&&r<=right) return segtree[pos][level]; int mid=(r+l)/2; ii a=query(pos*2+1,l,mid,left,right,level); ii b=query(pos*2+2,mid+1,r,left,right,level); //cout <<"sd"<<" "<<l<<" "<<r<<" "<<max(a.fi,b.fi)<<" "<<min(a.se,b.se)<<endl; return {max(a.fi,b.fi),min(a.se,b.se)}; } int main(){ optimise; //setIO("dec"); int n,k; cin>>n>>k; int m; cin>>m; int a[n+1]; int b[n+1]; for (int i = 0; i <= n; ++i) { a[i]=0; b[i]=1e9; } for (int i = 0; i < m; ++i) { int x,y; cin>>x>>y; if(x<y) a[x]=max(a[x],y); else b[x]=min(b[x],y); } multiset<int> st; int mx[n+1]; int mn[n+1]; for (int i = 0; i <= n; ++i) { if(i>=k){ st.erase(st.find(a[i-k])); } st.insert(a[i]); mx[i]=max(i,(*--st.end())); } st.clear(); for (int i = n; i >= 0; --i) { if(i<=n-k){ st.erase(st.find(b[i+k])); } st.insert(b[i]); //cout <<*st.begin()<<endl; mn[i]=min(i,(*st.begin())); } for (int i = 0; i <= nax*4; ++i) { for (int j = 0; j < 18; ++j) { segtree[i][j]={-1e9,1e9}; } } for (int i = 0; i <= n; ++i) { update(0,0,n,i,{mx[i],mn[i]},0); //cout <<mx[i]<<" "<<mn[i]<<endl; } for (int i = 1; i < lg; ++i) { for (int j = 0; j <= n; ++j) { ii a=query(0,0,n,mn[j],mx[j],i-1); //cout <<mn[j]<<" "<<mx[j]<<" "<<a.fi<<" "<<a.se<<endl; update(0,0,n,j,a,i); mx[j]=a.fi; mn[j]=a.se; //cout <<mn[j]<<" "<<mx[j]<<endl; } } int q; cin>>q; while(q--){ int s,t; cin>>s>>t; if(t<mn[s]||t>mx[s]) { cout <<-1<<'\n'; continue; } int ans=0; ii cur={s,s}; for (int i = 16; i >=0 ; --i) { ii nxt=query(0,0,n,cur.se,cur.fi,i); if(t>nxt.fi||t<nxt.se){ cur=nxt; ans+=(1<<i); } } cout <<ans+1<<'\n'; } }

컴파일 시 표준 에러 (stderr) 메시지

Main.cpp: In function 'void setIO(std::string)':
Main.cpp:35:12: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   35 |     freopen((s + ".in").c_str(), "r", stdin);
      |     ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Main.cpp:36:12: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   36 |     freopen((s + ".out").c_str(), "w", stdout);
      |     ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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