Submission #954333

#	Time	Username	Problem	Language	Result	Execution time	Memory
954333		veljko	Sails (IOI07_sails)	C++17	10 / 100	21 ms	4048 KiB

sails

/*****from dust I have come, dust I will be*****/
#include<bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
 
using namespace __gnu_pbds;
using namespace std;
#define int long long
#define double long double
#define forn(i,n) for(int i=0;i<n;i++)
int dx[8] = { 1, 0, -1, 0, -1, 1, -1, 1 };
int dy[8] = { 0, 1, 0, -1, -1, 1, 1, -1 };
int ceil_div(int a, int b) {return a % b == 0 ? a / b : a / b + 1;}
 
const int MOD = 1000000007;
//const int MOD = 998244353;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> pbds; // find_by_order, order_of_key
 
/*
int k = A.order_of_key(p[i].second);
A.erase(A.find_by_order(k));
erase element from pbds multiset
*/

//ako hocemo da broj sk, predstavimo
//kao zbir k cifara, a da te cifre budu
//najvece moguce
void sumk(vector<int>&ans, int sk, int k){
    for(int i = 0; i < k; i++) {
        ans[i] += sk / k;
        if (sk % k != 0) ans[i]++, sk--;		 	
    }
}

int formula(int n){
    return (n * (n + 1) / 2);
}

void solve(){
    int n; cin >> n;
    vector<int>a(n);
    int sum = 0;
    forn(i,n){
        int s;
        cin >> a[i]>> s;
        sum += s;
    }
    sort(a.begin(), a.end());
    int ukupno = n;
    vector<int>b;
    int p1 = 0;
    for (int i=1;i<=a.back();i++){
        while (p1 < n && i > a[p1]){
            p1++;
            ukupno--;
        }
        b.push_back(ukupno);
    }
    int prev = 0;
    vector<int>tmp((int)b.size() + 1);
    for (int i=(int)b.size()-1;i>=0;i--){
        int br = i + 1;
        int x = (b[i] - prev) * br;
        if (x <= sum){
            tmp[0] += (b[i] - prev);
            tmp[(int)b.size()] -= (b[i] - prev);
            sum -= x;
        }
        else{
            for (int i=1;i<(int)b.size();i++) tmp[i] += tmp[i-1];
            sumk(tmp, sum, br);
            // for (int i=0;i<(int)b.size();i++) cout <<tmp[i]<<' ';
            // cout <<'\n';
            break;
        }
        prev = b[i];
    }
    int ans = 0;
    for (int i=0;i<(int)b.size();i++) ans += formula(tmp[i]-1);
    cout <<ans<<'\n';
}
 
int32_t main(){
    ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);


    
    int t = 1; //cin >>t;
    for (int i=1;i<=t;i++){
        solve();
    }
    return 0;
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 10
• Subtask 3: 10 / 10
• Subtask 4: 0 / 5
• Subtask 5: 0 / 10
• Subtask 6: 0 / 10
• Subtask 7: 0 / 10
• Subtask 8: 0 / 10
• Subtask 9: 0 / 10
• Subtask 10: 0 / 10
• Subtask 11: 0 / 10